Question

ASAP PLS PLSLSLSLSLSLSSL

Answer 1

Answer:

BDCEA

Step-by-step explanation:

A: area of the triangle = $\frac{1}{2}bh = \frac{1}{2}(10)(4) = \frac{1}{2}(40) = 20 ft^{2}$

B: area of the rectangle + area of the triangle =$(5*6) + \frac{1}{2}(5)(6) = 30+15=45 ft^{2}$

C: area of the rectangle + area of the trapezoid = $(6*2) + \frac{1}{2}(b_{1} +b_{2})(h) = (6*2)+ \frac{1}{2}(2+5)(5) = 12+\frac{1}{2}(35) = 29.5 ft^2$

E: area of the triangle = $\frac{1}{2}bh = \frac{1}{2}(14)(4) = \frac{1}{2}(56) = 28 ft^{2}$

D: area of the rectangle + area of the triangle = $(8*3) + \frac{1}{2}(8)(2) = 24+8=32 ft^{2}$