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Marina86 [1]
3 years ago
11

Solve for the variable 12=5x+7

Mathematics
1 answer:
masya89 [10]3 years ago
4 0

Answer:

would the variable be like one or something because 7 plus 5 is just 12 and that variable isn't needed so postive one

Step-by-step explanation:

brainlist plz thx

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You collect a total of $75 in donations from three people. The three donations are in the ratio 4 to 4 to 7. How much is each of
worty [1.4K]
Each smaller donation was for $20 The largest donation was $15 greater than the smaller donation. First, determine the size of each donation. Since they are in a ratio of 4:4:7, it's easiest to add the ratios together (4+4+7) = 15. Then divide the total donation by that sum (75/15) = 5. Finally, multiply 5 by each of the ratios. 5 * 4 = 20, 5 * 4 = 20, and 5 * 7 = 35 So the 2 smaller donations were $20 each, and the largest donation was for $35. The largest donation was $35 - $20 = $15 larger than one of the smaller donations.
7 0
3 years ago
How do u solve this question in the picture
dedylja [7]
1/2 over -2/5 + (-1/4) 

10/20 over -8/20 + (-5/20) 

1 5/20 + (-5/20) 

1

The answer is 1
6 0
3 years ago
Solving multistep linear equations and inequalities<br>help me please​
butalik [34]

Answer:

Step-by-step explanation:

Part A:

C = 10t + s

Part B:

10(3) + 8

30 + 8 = $38

5 0
3 years ago
Expand the given power by using Pascal’s triangle. (9a - 10b)^6
xxMikexx [17]

Answer:

531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

Step-by-step explanation:

                     1                                n=0

                  1      1                            n=1

                 1   2   1                           n=2

                1  3  3  1                          n=3

              1  4  6  4   1                      n=4

             1  5 10 10 5  1                    n=5

           1 6 15 20 15 6 1                   n=6

This is where n is the exponent in

(x+y)^n.

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

Now we want to expand:

(9a-10b)^6 or we we can rewrite as (9a+(-10b))^6.

Let's replace x with (9a) and y with (-10b) in the expansion:

(x+y)^6=1x^6+6x^5y+15x^4y^2+20x^3y^3+15x^2y^4+6xy^5+1y^6

((9a)+(-10b))^6

=1(9a)^6+6(9a)^5(-10b)+15(9a)^4(-10b)^2+20(9a)^3(-10b)^3+15(9a)^2(-10b)^4+6(9a)(-10b)^5+1(-10b)^6

Let's simplify a bit:

=9^6a^6-60(9)^5a^5b+15(-10)^2(9)^4a^4b^2+20(9)^3(-10)^3a^3b^3+15(9)^2(-10)^4a^2b^4+6(9)(-10)^5ab^5+(-10)^6b^6

=531441a^6-3542940a^5b+9841500a^4b^2-14580000a^3b^3+12150000a^2b^4-5400000ab^5+1000000b^6

8 0
4 years ago
mf help please!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Andrej [43]

Answer:

Your answer is A.

Hope this helps!

Step-by-step explanation:

Line r's equation is

y = - 4/3x - 4

And Line s's equation is

y = 2/5x - 2

4 0
3 years ago
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