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3 years ago

I need help please help

Mathematics

1 answer:

saveliy_v [14]3 years ago

3 0

Answer:(0,6)

Step-by-step explanation:

Solve for Y if X =0

y=2x+6

Y=2(0)+6

Y=6

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The product of 5 and twice a number

Stells [14]

Product means multiply so:

5(2n)
=10n

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3 years ago

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Simplify 2 to the 5 power to the fourth power over 3 to the second power

melisa1 [442]

I'm assuming you mean 2^(5)(4/3)(2).
So multiplying all of the powers together yields 2^(40/3)

4 0

3 years ago

I NEED HELP PLEASE

VLD [36.1K]

Answer:

y=2x+13

Step-by-step explanation:

find gradient which is -2

-7-3/0--5=-10/5 =-2

y-3 =-2. (cross multiply)

x--5

y-3=2x+10

y=2x+13

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3 years ago

If f(x) = x + 7 and g(x) = 1 / x - 13, whaf is the domain of (f°g)(x)?

ZanzabumX [31]

Answer: Choice D) x can be anything but 13

========================================================

Explanation:

The domain of $(f \circ g)(x) = f(g(x))$ is the same as the domain of g(x)

The domain for g(x) is $\{x|x \ne 13\}$ saying we can plug in any number we want as long as it's not 13. This is to avoid dividing by zero. The same domain applies for the composite function because

$f(x) = x+7\\\\\\f(g(x)) = g(x)+7\\\\\\f(g(x)) = \frac{1}{x-13}+7\\\\\\(f \circ g)(x) = \frac{1}{x-13}+7\\\\\\$

and we can see that we still need to kick out x = 13 from the domain to avoid the division by zero issue.

6 0

3 years ago

Given the right angle triangle shown here, calculate:

charle [14.2K]

Answer:

see explanation

Step-by-step explanation:

(1)

(a)

sin(a) = $\frac{opposite}{hypotenuse}$ = $\frac{15}{17}$

(b)

cos(a) = $\frac{adjacent}{hypotenuse}$ = $\frac{8}{17}$

(c)

tan(a) = $\frac{opposite}{adjacent}$ = $\frac{15}{8}$

----------------------------------------------------

(2)

(a)

sin(b) = $\frac{opposite}{hypotenuse}$ = $\frac{8}{17}$

(b)

cos(b) = $\frac{adjacent}{hypotenuse}$ = $\frac{15}{17}$

(c)

tan(b) = $\frac{opposite}{adjacent}$ = $\frac{8}{15}$

5 0

3 years ago

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