I would say it’s B because out of ten it makes the mean 1 point higher
The standard form of a quadratic equation is

, while the vertex form is:

, where (h, k) is the vertex of the parabola.
What we want is to write

as

First, we note that all the three terms have a factor of 3, so we factorize it and write:

.
Second, we notice that

are the terms produced by

, without the 9. So we can write:

, and substituting in

we have:
![\displaystyle{ y=3(x^2-6x-2)=3[(x-3)^2-9-2]=3[(x-3)^2-11]](https://tex.z-dn.net/?f=%5Cdisplaystyle%7B%20y%3D3%28x%5E2-6x-2%29%3D3%5B%28x-3%29%5E2-9-2%5D%3D3%5B%28x-3%29%5E2-11%5D)
.
Finally, distributing 3 over the two terms in the brackets we have:
![y=3[x-3]^2-33](https://tex.z-dn.net/?f=y%3D3%5Bx-3%5D%5E2-33)
.
Answer:
That would be 950 * 0.62 = 589 British pounds.
Answer: 10k
Step-by-step explanation:
Answer: 0=0
Step-by-step explanation:
First you want to solve for x
2x+y=−4
Step 1: Add -y to both sides.
2x + y + −y =−4+ −y
2x=−y−4
Step 2: Divide both sides by 2.
2x/2= -y-4/2
x=-1/2y-2
Then you want to plug in your answer for x into the equation so:
2(-1/2y-2)+y=-4
Step 1: Simplify both sides of the equation.
2(-1/2y-2)+y=-4
(2)(
−1/
2
y)+(2)(−2)+y(Distribute)
−y+−4+y=−4
(−y+y)+(−4)=−4(Combine Like Terms)
−4=−4
−4=−4
Step 2: Add 4 to both sides.
−4+4=−4+4
0=0.
Sorry if this wasn't the answer your looking for. If you need more help I suggest using Ma.th.Pa.pa calculator but with out the periods. Hope you have a good day :)