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melomori [17]
3 years ago
5

Which equation can be used to solve a – 5 = 30?

Mathematics
1 answer:
il63 [147K]3 years ago
6 0

Answer:

25 sobra as una suma y una división y veras a 30 le quitas 5 te quedan 25

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A taxi charges $3.00 to pick you up and $1.00 for every mile driven. How could
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1x +3= T

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x is the number of miles driven times 1

add 3 to the total charge per miles

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What is the solution to a system of linear equations if the answer is -3=-3?
Vsevolod [243]

Answer:

No solution

Step-by-step explanation:

So the equation is saying that -3 is equal to 3. But that is false so it would make the system of linear equations be no solution. Which means that you are giving a number that is equal to another number when its not. For example, lets say that you are given 4=-20 well that would be no solution because those aren't equal. Now lets say you are given 20=20 that would be infinitely many solutions because the two numbers are equal to each other.

Hope this helps

3 0
3 years ago
Show that (a - b)+(b-c)+(c -a)3 = 3 (a - b) (b -c) (c-a)​
nikdorinn [45]

Answer:

I think that it should be

{(a - b)}^{3}  +  {(b - c)}^{3}  +  {(c - a)}^{3}  = 3(a - b)(b - c)(c - a)

Step-by-step explanation:

Here,

we take , a - b = A,b-c = B , c - a= C

A+B+C = 0

we know that,

{a}^{3}  +  {b}^{3}  +  {c}^{3}   - 3abc = (a + b + c)(  {a}^{2}  +  {b}^{2}  +  {c}^{2}  - ab - bc - ca)

Here , A+B+C = 0

so,

A^3 +B^3 + C^3 = 3 ABC

now we put the values

{(a - b)}^{3}  +  {(b - c)}^{3}  +  {(c - a)}^{3}  = 3(a - b)(b - c)(c - a)

I am done .

4 0
4 years ago
Read 2 more answers
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