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Tju [1.3M]
3 years ago
13

Acute, obtuse, or right?

Mathematics
2 answers:
dimaraw [331]3 years ago
7 0
It would be obtuse.


Hope this helps :)
fiasKO [112]3 years ago
4 0
Because there are no angle measures to indicate whether a triangle is obtuse, acute, or right, yo find out, you must use the Pythagorean Theorem or
a^2+b^2=c^2 where a and b are the lengths of the shorter legs and c is the measure of the hypotenuse (or the slant).

To do this, plug in the values and if a^2+b^2 is greater than c^2, the triangle is acute. If a^2+b^2 is less than c^2, the triangle is obtuse. If a^2+b^2 is equal to c^2, then your triangle is a right triangle.

When you plug in your values you should get this:
6^2+\sqrt{133}^2=16^2

When you simplify, you should result in
36+133=256 which then simplifies to 169=256

Because 169 is less than 256 (the hypotenuse), you can conclude that this triangle is obtuse.
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notsponge [240]

3 scoops and a quarter? not really sure if you were saying one and a half cups or if the Baker was using ONE half cup scoop

1 1/2+1 1/2+1 1/2+ 1/4 =4.75

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3 years ago
Suma a trei numere este 30. Primul numar este de doua ori mai mare decat triplul celui de-al treilea numar si de doua ori mai ma
Sloan [31]
 a + b + c = 30 ;
a = 6c ;
a = 2b ;

Then, c = a / 6 and b = a / 2 ;
a / 6 + a / 2 + a = 30 ;
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Good luck !

4 0
3 years ago
Use the following table to help answer the question below.
MariettaO [177]

Answer:

d.

They could file for Chapter 13 bankruptcy and discharge some of their debt.

Step-by-step explanation:

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Which fractions are equivalent to 4/9? Choose Yes or No for each fraction. Please answer quickly i need this!
mamaluj [8]
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Read 2 more answers
A librarian has 4 identical copies of Hamlet, 3 identical copies of Macbeth, 2 identical copies of Romeo and Juliet, and one cop
lesantik [10]

Answer:

The number of distinct arrangements is <em>12600</em><em>.</em>

Step-by-step explanation:

This is a permutation type of question and therefore the number of distinguishable permutations is:

n!/(n₁! n₂! n₃! ... nₓ!)

where

  • n₁, n₂, n₃ ... is the number of arrangements for each object
  • n is the number of objects
  • nₓ is the number of arrangements for the last object

In this case

  • n₁ is the identical copies of Hamlet
  • n₂ is the identical copies of Macbeth
  • n₃ is the identical copies of Romeo and Juliet
  • nₓ = n₄ is the one copy of Midsummer's Night Dream

Therefore,

<em>Number of distinct arrangements =  10!/(4! × 3! × 2! × 1!)</em>

<em>                                                         = </em><em>12600 ways</em>

<em />

Thus, the number of distinct arrangements is <em>12600</em><em>.</em>

4 0
3 years ago
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