Acute, obtuse, or right?
2 answers:
Because there are no angle measures to indicate whether a triangle is obtuse, acute, or right, yo find out, you must use the Pythagorean Theorem or
a^2+b^2=c^2 where a and b are the lengths of the shorter legs and c is the measure of the hypotenuse (or the slant).
To do this, plug in the values and if a^2+b^2 is greater than c^2, the triangle is acute. If a^2+b^2 is less than c^2, the triangle is obtuse. If a^2+b^2 is equal to c^2, then your triangle is a right triangle.
When you plug in your values you should get this:
6^2+
^2=16^2
When you simplify, you should result in
36+133=256 which then simplifies to 169=256
Because 169 is less than 256 (the hypotenuse), you can conclude that this triangle is obtuse.
a^2+b^2=c^2 where a and b are the lengths of the shorter legs and c is the measure of the hypotenuse (or the slant).
To do this, plug in the values and if a^2+b^2 is greater than c^2, the triangle is acute. If a^2+b^2 is less than c^2, the triangle is obtuse. If a^2+b^2 is equal to c^2, then your triangle is a right triangle.
When you plug in your values you should get this:
6^2+
When you simplify, you should result in
36+133=256 which then simplifies to 169=256
Because 169 is less than 256 (the hypotenuse), you can conclude that this triangle is obtuse.
You might be interested in
Answer:
Step-by-step explanation:
Given equation can be re written as
............(i)
Now it is given that y(π/2) = 2e
Applying value in (i) we get
ln(2e) = sin(π/2) + c
=> ln(2) + ln(e) = 1+c
=> ln(2) + 1 = 1 + c
=> c = ln(2)
Thus equation (i) becomes
ln(y) = sin(x) + ln(2)
ln(y) - ln(2) = sin(x)
ln(y/2) = sin(x)