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Kryger [21]
3 years ago
7

Find the perimeter of the larger polygon if the two polygons are similar.

Mathematics
1 answer:
Lilit [14]3 years ago
8 0

Answer:

130.5

Step-by-step explanation:

similar shapes have proportional sides so divide 18/27 to get the proportion then multiply each side of the smaller polygon by the proportion to get the sides for the larger polygon and add the larger polygons sides together.

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Determine how many acute angels are in this figure
Zepler [3.9K]

Answer:21

Step-by-step explanation:

One = <AOB

two= <BOC

three = <COD

four = <DOE

five = <EOF

six = <AOC

Seven = <AOD

Eight = <AOE

Nine = <BOD

Ten = < BOE

Eleven = < BOF

Theres a bunch more but im not listing them

6 0
3 years ago
The tree in Debra's backyard is 6 meters high. How high is it in centimeters?
Maksim231197 [3]

Answer:

600 centimeters. 1 meter is equal to 100 centimeters

3 0
3 years ago
Write expression as a sine or cosine of an angle.<br>cos 94° cos 18° + sin 94° sin 18° ​
MArishka [77]
<h3>Answer:  cos(76)</h3>

=========================================================

Explanation:

The original expression is of the pattern cos cos + sin sin. This pattern matches the second identity in the hint. Specifically, we'll say the following:

cos(A - B) = cos(A)cos(B) + sin(A)sin(B)

cos(A)cos(B) + sin(A)sin(B) = cos(A - B)

cos(94)cos(18) + sin(94)sin(18) = cos(94 - 18)

cos(94)cos(18) + sin(94)sin(18) = cos(76)

----------

We can verify this by use of a calculator. Make sure your calculator is in degree mode.

  • cos(94)cos(18) + sin(94)sin(18) = 0.24192
  • cos(76) = 0.24192

Both expressions give the same decimal approximation, so this helps confirm the two expressions are equal. You could also use the idea that if x = y, then x-y = 0. Through this method, you'll subtract the left and right hand sides and you should get (very close to) zero.

6 0
2 years ago
Help is appreciated! Thanks!
sukhopar [10]

Answer:

  1. 16√3
  2. -45+15i
  3. √255
  4. 6√2 +3√10

Step-by-step explanation:

1)

-4i\sqrt{-48}=-4i\sqrt{(-1)(4^2)(3)}=(-4i)(4i)\sqrt{3}=16\sqrt{3}

__

2)

(-5-5i)(3-6i)=-5(3-6i)-5i(3-6i)=-15+30i-15i+30i^2=-15-30+15i\\\\=-45+15i

__

3)

\sqrt{3}\sqrt{5}\sqrt{17}=\sqrt{3\cdot 5\cdot 17}=\sqrt{255}

__

4)

\sqrt{3}(\sqrt{24}+\sqrt{30})=\sqrt{3\cdot 24}+\sqrt{3\cdot 30}=\sqrt{6^2\cdot 2}+\sqrt{3^2\cdot 10}\\\\=6\sqrt{2}+3\sqrt{10}

_____

The applicable identities are ...

\sqrt{a^2b}=a\sqrt{b}\\\\i^2=-1

7 0
3 years ago
Read 2 more answers
Negative positive or no association
Eddi Din [679]

Answer:

Positive association

Step-by-step explanation:

As the Temperature goes up the more money you have to spend because you pay for the electricity that produces the heat

positive association is when one varriable increases so does the other.

7 0
2 years ago
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