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melisa1 [442]
2 years ago
8

Which of the following objects show an OBTUSE angle?

Mathematics
2 answers:
antiseptic1488 [7]2 years ago
6 0
And obtuse angle is greater than 90°
givi [52]2 years ago
3 0
An obtuse angle has a measurement greater than 90 degrees but less than 180 degrees.
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An outdoor hockey rink has dimensions of 8m long by 5m wide. The wood
amid [387]

Answer:

First question = 800 cm^3

Second question =120π

Step-by-step explanation:

The formula for volume is base x height x width.

The formula for area of cylinder is 2πrh+2πr^2 but it has no lid so

2πrh+πr^2.

4 0
3 years ago
At the middle school graduation dance, the DJ played 12 slow dances, which was equal to the quotient of the number of fast dance
belka [17]

quotient means divide

 so 12 = x/2

x = 12*2 = 24

 x =24 fast songs

3 0
3 years ago
Latrell bought 4 bags of powdered sugar. He got a total of 5 1/2 cups of sugar. How many cups of sugar were in each bag?
Stels [109]
So all 4 bags of sugar yielded 5 and 1/2 cups..... well.. how many in each one?  well, let's split the 5 and 1/2 evenly in 4 pieces.

\bf \stackrel{mixed}{5}\frac{1}{2}\implies \cfrac{5\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{11}{2}}\\\\
-------------------------------\\\\
\cfrac{\quad\frac{11}{2} \quad }{4}\implies \cfrac{\quad\frac{11}{2} \quad }{\frac{4}{1}}\implies \cfrac{11}{2}\cdot \cfrac{1}{4}\implies \cfrac{11}{8}\implies \stackrel{cups}{1\frac{3}{8}
}
5 0
3 years ago
On Monday, three hundred ninety - two students went on a trip to the zoo. All nine buses were filled and five students had to tr
Vikki [24]
The answer to your question is 43
5 0
3 years ago
(I've been trying to figure this out for 3 days and I really need help)
liq [111]

Check the picture below.

since the diameter of the cone is 6", then its radius is half that or 3", so getting the volume of only the cone, not the top.

1)

\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\cfrac{\pi (3)^2(4)}{3}\implies V=12\pi \implies V\approx 37.7

2)

now, the top of it, as you notice in the picture, is a semicircle, whose radius is the same as the cone's, 3.

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=3 \end{cases}\implies V=\cfrac{4\pi (3)^3}{3}\implies V=36\pi \\\\\\ \stackrel{\textit{half of that for a semisphere}}{V=18\pi }\implies V\approx 56.55

3)

well, you'll be serving the cone and top combined, 12π + 18π = 30π or about 94.25 in³.

4)

pretty much the same thing, we get the volume of the cone and its top, add them up.

\bf \stackrel{\textit{cone's volume}}{\cfrac{\pi (3)^2(8)}{3}}~~~~+~~~~\stackrel{\stackrel{\textit{half a sphere}}{\textit{top's volume}}}{\cfrac{4\pi 3^3}{3}\div 2}\implies 24\pi +18\pi \implies 42\pi ~~\approx~~131.95~in^

8 0
3 years ago
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