The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
Learn more about work done here:
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Well, they're saying 9 with an exponet of 2 multiplied by something equals 27..... Hmmm.....
Answer:
m= 4
Step-by-step explanation:
3m +2n= 16 -----(1)
m -2n= 0 -----(2)
From (2):
m= 2n -----(3) (+2n on both sides)
subst. (3) into (1):
3(2n) +2n= 16
6n +2n= 16
8n= 16 (simplify)
n= 16 ÷8
n= 2
subst. n=2 into (3):
m= 2(2)
m= 4
Step-by-step explanation:
2.5 hours = 150 min
1/3 of 150 is 50 min, which means she spent 50 min on her history project = 100 min leftover
3/5 of 100 min is 60 min (1 hour) = 40 min leftover
She spent 40 min writing her essay
hope this helps <3
