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3 years ago

Solve equation 3x-5y=7 5x-2y=-1 by elimination

Mathematics

2 answers:

kakasveta [241]3 years ago

7 0

Answer:

x = -1, y = -2.

Step-by-step explanation:

Using the elimination method,

multiply the first eqn by 2 and the 2nd eqn by 5.

6x - 10y = 14

25x - 10y = -5

Subtract one of the new equations from the other

-19x = 19

x = -1

Sub x=-1 into the 2nd eqn

-5 - 2y = -1

y = -2

Hence x = -1, y = -2.

jarptica [38.1K]3 years ago

5 0

Answer: x= -1, y= -2

Step-by-step explanation:

Multiply both sides of the equation by -2.

-6x + 10y= -14

5x - 2y= -1

Sum the equations vertically to eliminate at least one variable.

19x= -19

Divide both sides of the equation by 19.

x=-1

Substitute the given value of x into the equation 5x (-1) - 2y= -1.

Solve the equation for y.

y=-2

The possible solution of the system is the ordered pair (x,y)

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Answer:

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4 years ago

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3 years ago

Read 2 more answers

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Answer:

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3 years ago

Jared made 12 3/4 cups of snack mix for a party.His guests eat 2/3 of the mix.How manysnack mix did his guest eat?

Fantom [35]

Answer:

<h3>The number of snacks did Jared's guest eat is $12\frac{1}{12}$ </h3>

Step-by-step explanation:

Given that Jared made $12\frac{3}{4}$ cups of snack mix for a party.

Let x be the cups of snacks mix made by Jared.

Therefore $x=12\frac{3}{4}$

His guests eat $\frac{2}{3}$ of the mix.

Let y be the guest eated snacks mix

Therefore $y=\frac{2}{3}$

<h3>To find how many snack mix did his guest eat :</h3>

Let z be the number of snacks did Jared's guest eat

Therefore z=x-y

$z=12\frac{3}{4}-\frac{2}{3}$

$=\frac{51}{4}-\frac{2}{3}$

$=\frac{51(3)-2(4)}{4\times 3}$

$=\frac{153-8}{12}$

$=\frac{145}{12}$

$=12\frac{1}{12}$

Therefore $z=12\frac{1}{12}$

<h3>Therefore the number of snacks did Jared's guest eat is $12\frac{1}{12}$ </h3>

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