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worty [1.4K]
2 years ago
14

Hellpepepeepe meeeee

Mathematics
1 answer:
Xelga [282]2 years ago
3 0
Are those the only suggestions
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When Peyton left her house this morning, her cell phone was 70% charged and it then
Katyanochek1 [597]

Answer:

I don't know for sure, but it might be 70%=5%(t)

4 0
3 years ago
What are the coordinates of the fourth point that could be connected with (–8, 0), (1, 0), and (1, –5) to form a rectangle?
Ksju [112]
(-8,-5). If you think about it, for a rectangle, the x-coordinates must be the same in two pairs and the y-coordinates must be the same in two pairs. Since there are already 2 0's, 2 1's, you need a -8 and -5 to complete it. Hence, the last coordinate is (-8,-5)
5 0
3 years ago
Describe a method you can use to find the area of the following shape. Provide specific details in your answer, including coordi
Advocard [28]

There are a number of ways this can be done. One that is fairly simple is as follows.

Triangle ABC has base AC = 9 and height B to AC of 3 (found by counting squares). Thus its area is ∆ABC = (1/2)·9·3 = 13.5 square units.

Triangle ACF has base AC = 9 and height F to AC of 3, so will have the same area as triangle ABC, 13.5 square units.

Trapezoid CDEF has base CD of 6, base EF of 4 and height EF to CD of 6 (found by counting squares). Thus its area is CDEF = (1/2)(6 + 4)(6) = 30.

The total area of the entire figure is then

... ∆ABC + ∆ACF + CDEF = 13.5 + 13.5 + 30 = 57 square units.

7 0
3 years ago
Write these in standard form :
kotegsom [21]

8.23\cdot10^6=8.23\cdot1,000,000=8,230,000\\\\2.4\cdot10^5=2.4\cdot100,000=240,000

\text{The scientific notation:}\ a\cdot10^n\ (1\leq a < 10,\ n\in\mathbb{Z})\\\\4\underbrace{50000}_{\leftarrow5}=4.5\cdot10^5\\\\320=3.2\cdot100=3.2\cdot10^2\\\\0.\underbrace{0000006}_{7\rightarrow}73=6.73\cdot10^{-7}\\\\3\underbrace{2100000}_{\leftarrow7}=3.12\cdot10^7

7 0
3 years ago
CAN SOMEONE PLEASE HELP ME. ITS HARD AND I CANT SOLVE IT. ILL MARK BRAINLIEST
S_A_V [24]

Answer:

Step-by-step explanation:

Hello,

First of all, we need to find the equation of the line.

It will be something like y = ax + b (we need to find a and b).

Then the graph is the part of the plan which is above this line, so the inequality will be

\large \boxed{\sf  \ \ y\geq ax+b \ \ }

There is only one line passing by two different points, right?

We need to find two points of this line, the x-axis gives the x of the point and the y-axis give the y of the point.

We can see on the graph that (-1,-1) and (6,13) are two points of this line.

I attached a graph with the two points A (-1,-1) and B (6,13).

We need to solve y = ax + b to find a and b which means:

(-1) = a(-1 )+ b <=> -1 = -a + b <=> -a + b = -1

(13) = a(6) + b <=> 6a + b = 13

To eliminate b, we can subtract the first equation from the second one.

6a + b -(-a) - b = 13 - (-1) = 13 + 1 = 14

<=> 6a + a = 7a = 14 we can divide by 7 both parts of the equation.

\large \boxed{\sf \ \ a=\dfrac{14}{7}=2 \ \ }

And then, b = -1 + a = -1 + 2 = 1

\large \boxed{\sf \ \ b=1 \ \ }

The equation of the line is then y=2x+1

So, the inequality is:

\Large \boxed{\sf \ \ y\geq 2x+1 \ \ }

And this is the answer of the question 1.

2. First, we find the equation of the line by finding two points on this line. Then, we deduce the inequality from the equality as the graph is all the points above the line (as explained above).

3. A real-life example is the following.

My parents gave $1 to my sister and they will give her $2 every day.

So today at x = 0 she has $1 and her pocket money will be represented by the line. And I told my parents that there were no way I can get less than my little sister. To help them understand what can be an acceptable deal I provided this graph, and I told them to only look for t positive of course.

The label for the x-axis is the time.

The label for the y-axis is the pocket money in $

After one day x = 1 my sister has $3 (point on the line), a possible solution for my pocket money is $6, $14 (two points from the graph) is also a solution of course :-)

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

4 0
3 years ago
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