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GuDViN [60]
3 years ago
11

Heeeeeeeelppppppppppppp plz plz i will mark you brill please just if you help

Mathematics
2 answers:
Nadya [2.5K]3 years ago
8 0
The answer is in the image I have attached, hope it helps.

user100 [1]3 years ago
4 0
Use the picture for reference, label all the numbers down 1-23, and for each number that is on the list put a dot, so for number 1 it would have 2 dots above it because there are 2 number 1’s in the list. And so on.

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What value of x would satisfy the equation 6x-4(2x+1)= 10 as a improper fraction
Serga [27]
X= -7
Hope it helps......
5 0
3 years ago
Use partial quotients to solve 504 divide 14
miv72 [106K]

Answer:

Perform the following division using partial quotients: 504 ÷ 14:

To reduce the numerator, we will be multiplying the denominator by factors of 10, 5, 2, and 1

Step-by-step explanation:

1 4| 5 0 4

2 8 0 20 <---- 20 x 14 = 280

2 2 4 <---- 504 - 280 = 224

1 4| 5 0 4

2 8 0 20

2 2 4

1 4 0 10 <---- 10 x 14 = 140

8 4 <---- 224 - 140 = 84

1 4| 5 0 4

2 8 0 20

2 2 4

1 4 0 10

8 4

7 0 5 <---- 5 x 14 = 70

1 4 <---- 84 - 70 = 14

1 4| 5 0 4

2 8 0 20

2 2 4

1 4 0 10

8 4

7 0 5

1 4

1 4 1 <---- 1 x 14 = 14

0 <---- 14 - 14 = 0

Our partial quotients add up as follows:

20 + 10 + 5 + 1 = 36

I hope it helps plz Mark me brainliest:)

5 0
3 years ago
Please Help!!
Genrish500 [490]

Given

a\sqrt{x+b}+c=d

we have

\sqrt{x+b}=\dfrac{d-c}{a}

Squaring both sides, we have

x+b=\dfrac{(d-c)^2}{a^2}

And finally

x=\dfrac{(d-c)^2}{a^2}-b

Note that, when we square both sides, we have to assume that

\dfrac{d-c}{a}>0

because we're assuming that this fraction equals a square root, which is positive.

So, if that fraction is positive you'll actually have roots: choose

a=1,\ b=0,\ c=2,\ d=6

and you'll have

\sqrt{x}+2=6 \iff \sqrt{x}=4 \iff x=16

Which is a valid solution. If, instead, the fraction is negative, you'll have extraneous roots: choose

a=1,\ b=0,\ c=10,\ d=4

and you'll have

\sqrt{x}+10=4 \iff \sqrt{x}=-6

Squaring both sides (and here's the mistake!!) you'd have

x=36

which is not a solution for the equation, if we plug it in we have

\sqrt{x}+10=4 \implies \sqrt{36}+10=4 \implies 6+10=4

Which is clearly false

7 0
3 years ago
Is 5.2 greater than 60.3
yanalaym [24]
No, it is not. If you see closely, the number 5.2 is not 52. 60 is greater than 5.2.
4 0
4 years ago
Read 2 more answers
Using the numbers and symbols, solve 7x = 42
spin [16.1K]

Answer:

you currently have the value of x × 7, you need to divide it by 7 to find the value of x.

42 ÷ 7 = 6

Step-by-step explanation:

4 0
3 years ago
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