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Harman [31]
3 years ago
11

) (i) Simplify:Permudahkan:-9 + 3t - 4​

Mathematics
1 answer:
AURORKA [14]3 years ago
3 0

Answer: =3t+5

Step-by-step explanation:

hope this helped

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In a previous​ year, 58​% of females aged 15 and older lived alone. A sociologist tests whether this percentage is different tod
Gemiola [76]

Answer:

z=\frac{0.565 -0.58}{\sqrt{\frac{0.58(1-0.58)}{600}}}=-0.744  

Since is a bilateral test the p value would be given by:  

p_v =2*P(z  

And since the p value is higher than the significance level we have enough evidence to conclude that the true proportion is not significantly different from 0.58

Step-by-step explanation:

Information given

n=600 represent the random sample selcted

X=339 represent the number of females aged 15 and older that living alone

\hat p=\frac{339}{600}=0.565 estimated proportion of females aged 15 and older that living alone

p_o=0.58 is the value that we want to check

\alpha=0.01 represent the significance level

z would represent the statistic

p_ represent the p value

Sytem of hypothesis

We want to check if the true proportion females aged 15 and older that living alone is significantly different from 0.58.:  

Null hypothesis:p=0.58  

Alternative hypothesis:p \neq 0.58  

The statistic is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the info given we got:

z=\frac{0.565 -0.58}{\sqrt{\frac{0.58(1-0.58)}{600}}}=-0.744  

Since is a bilateral test the p value would be given by:  

p_v =2*P(z  

And since the p value is higher than the significance level we have enough evidence to conclude that the true proportion is not significantly different from 0.58

5 0
3 years ago
Which equation is the slope intercept form of this equation?
AnnZ [28]

Answer:

C

Step-by-step explanation:

Y - 4 = -2x + 10 Multiply -2 to the inside the brackets

Y = -2x + 14 Add the 4 over

7 0
3 years ago
A 90% confidence interval for the mean height of students
Westkost [7]

Answer:

ME= \frac{69.397-60.128}{2}= 4.6345 \approx 4.635

And the best answer on this case would be:

b) m = 4.635

Step-by-step explanation:

Let X the random variable of interest and we know that the confidence interval for the population mean \mu is given by this formula:

\bar X \pm t_{\alpha/2} \frac{s}{\sqrt{n}}

The confidence level on this case is 0.9 and the significance \alpha=1-0.9=0.1

The confidence interval calculated on this case is 60.128 \leq \mu \leq 69.397

The margin of error for this confidence interval is given by:

ME =t_{\alpha/2} \frac{s}{\sqrt{n}}

Since the confidence interval is symmetrical we can estimate the margin of error with the following formula:

ME = \frac{Upper -Lower}{2}

Where Upper and Lower represent the bounds for the confidence interval calculated and replacing we got:

ME= \frac{69.397-60.128}{2}= 4.6345 \approx 4.635

And the best answer on this case would be:

b) m = 4.635

4 0
3 years ago
I need help finding the answer for this.​
Dmitry [639]
The Answer is 12 meters.
7 0
3 years ago
Use the triangle below to find cos V.
Semenov [28]

Answer:

cos\ V = \frac{2\sqrt{29}}{29}

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

cos\theta = \frac{Adjacent}{Hypotenuse}

In this case:

cos V= \frac{TV}{UV}

Where

TV = 6

and

UV^2 = TV^2 + TU^2 -- Pythagoras

UV^2 = 6^2 + 15^2

UV^2 = 261

Take square roots

UV = \sqrt{261

UV = \sqrt{9*29

UV = \sqrt{9} *\sqrt{29

UV = 3\sqrt{29

So:

cos V= \frac{TV}{UV}

cos\ V = \frac{6}{3\sqrt{29}}

cos\ V = \frac{2}{\sqrt{29}}

Rationalize:

cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}

cos\ V = \frac{2\sqrt{29}}{29}

8 0
3 years ago
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