V1=(T1/T2)*V2
In this problem, since you are given no actual numbers, the only thing you can do is multiply V2 over to get V1 alone. Since you can't cancel anything out, you are left with the answer above.

4 0

3 years ago

I need help on this question

kherson [118]

Answer:

Step-by-step explanation:

Just put x = 80 and y = 210 into the equation...

or put x = 40, y = 90.

210 - 90 = 3(80-40)

120 = 120√

210 + 90 = 3(80+40)

300 = 360×

210 - 90 = 2.6(80-40)

120 = 104×

210 + 90 = 2.6(80+40)

300 = 312×

8 0

3 years ago

Use the distance formula, show that the points (4,0), (2,1), and (-1,-5) form the vertices of a right triangle

mario62 [17]

Step-by-step explanation:

The distance formula between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the points.

$A(4,\ 0),\ B(2,\ 1),\ C(-1,\ -5)\\\\AB=\sqrt{(2-4)^2+(1-0)^2}=\sqrt{(-2)^2+1^2}=\sqrt{4+1}=\sqrt5\\\\AC=\sqrt{(-1-4)^2+(-5-0)^2}=\sqrt{(-5)^2+(-5)^2}=\sqrt{25+25}=\sqrt{50}\\\\BC=\sqrt{(-1-2)^2+(-5-1)^2}=\sqrt{(-3)^2+(-6)^2}=\sqrt{9+36}=\sqrt{45}$