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Scrat [10]
3 years ago
15

a pound of chocolate costs 8 dollars. Felipe buys p pounds. write an equation to represent the total cost c that felipe pays

Mathematics
1 answer:
alisha [4.7K]3 years ago
6 0

Answer:

c=8p

Step-by-step explanation:

So, we know that 1 pound of chocolate will cost $8. Felipe is going to buy "p" pounds of chocolate, and "p" means "any number"; so Felipe is going to buy any number of pounds of chocolate.

The formula we would use to calculate this is cost of one pound of chocolate multiplied by number of pounds of chocolate. And the way we can form this algebraically is by writing c=8p.

The "c" stands for total cost and we don't have to put the multiply sign when using algebra, as long as the figures are touching.

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(3a^4b)(5ab^2)-(a^5b^2)(9b)
Sliva [168]

Answer:

The expanded value of the given expression is

(3a^4b)(5ab^2)-(a^5b^2)(9b)=6a^5b^3

Step-by-step explanation:

Given expression is                                                                              

(3a^4b)(5ab^2)-(a^5b^2)(9b)

To find the value of the given expression:

(3a^4b)(5ab^2)-(a^5b^2)(9b)=15a^5b^3-9a^5b^3

(By multiplying the products and doing algebraci subtracion of the above expression)

Now taking the common terms in the above equation we get

(3a^4b)(5ab^2)-(a^5b^2)(9b)=3a^5b^3(5-3)

                                             =3a^5b^3(2)

                                             =6a^5b^3

Therefore the expanded value of the given expression is

(3a^4b)(5ab^2)-(a^5b^2)(9b)=6a^5b^3

5 0
3 years ago
What is f(2) for f(x)=2x^4-5x^2-3x+2
zysi [14]
2(2^4) - 5(2^2) - 3*2 + 2 = 32-20-6+2 = 8
8 0
3 years ago
Read 2 more answers
Write the expression as either the sine, cosine, or tangent of a single angle. (2 points)
sattari [20]

Answer:

cos(π/3)cos(π/5) + sin(π/3)sin(π/5) = cos(2π/15)

Step-by-step explanation:

We will make use of trig identities to solve this. Here are some common trig identities.

Cos (A + B) = cosAcosB – sinAsinB

Cos (A – B) = cosAcosB + sinAsinB

Sin (A + B) = sinAcosB + sinBcosA

Sin (A – B) = sinAcosB – sinBcosA

Given cos(π/3)cos(π/5) + sin(π/3)sin(π/5) if we let A = π/3 and B = π/5, it reduces to

cosAcosB + sinAsinB and we know that

cosAcosB + sinAsinB = cos(A – B). Therefore,

cos(π/3)cos(π/5) + sin(π/3)sin(π/5) = cos(π/3 – π/5) = cos(2π/15)

8 0
3 years ago
Fifthy-four times three
larisa [96]

Answer:

162

Step-by-step explanation:

54 * 3 = 162

hope it's helpful

8 0
3 years ago
Read 2 more answers
What us (2-3i)+(8-2i)
Otrada [13]
(2 - 3i) + (8 - 2i)

Get rid of all of the parenthesis.

2 - 3i + 8 - 2i

Combine like terms.

(-3i - 2i) + (2 + 8)

Simplify.

-5i + 10

~Hope I helped!~
7 0
3 years ago
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