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goldfiish [28.3K]
4 years ago
10

Someone please help me with number 6. Also show your work as that will help a lot

Mathematics
1 answer:
adoni [48]4 years ago
7 0

\bf f(x) = x^2+3x+9 \\\\[-0.35em] ~\dotfill\\\\ \cfrac{(x+h)^2+3(x+h)+9~~~~-~~~~(x^2+3x+9)}{h} \\\\\\ \cfrac{(x+h)^2+3(x+h)+9~~~~~~-x^2-3x-9}{h} \\\\\\ \cfrac{\stackrel{F~~O~~I~~L}{(x^2+2hx+h^2)}+3x+3h+9~~~~~~-x^2-3x-9}{h}

\bf \cfrac{(2hx+h^2+3h)~~\begin{matrix} +x^2-x^2+3x-3x+9-9 \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~}{h}\implies \cfrac{\stackrel{\textit{common factor}}{~~\begin{matrix} h \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~(2x+h+3)}}{~~\begin{matrix} h \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill 2x+h+3~\hfill

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Step-by-step explanation:

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Step-by-step explanation:

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svp [43]

Answer:

The answer is "2x-y=4"

Step-by-step explanation:

Given:

2x-y=-4\\2x-y=4\\y=2x-4\\y=\frac{1}{2}(x-4)\\

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by replacing the (2,0) and (0,-4) coordinates in the above formula:

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5 0
4 years ago
Read 2 more answers
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scoundrel [369]
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Step-by-step explanation:

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