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andreev551 [17]
3 years ago
8

If the federal reserve decreases the reserve rate from 10% to 80% how does this affect the amount of money that would result bec

ause a fractional reserve banking from an initial deposit into a bank of $40,000
Mathematics
1 answer:
OLga [1]3 years ago
3 0

Answer:

100,000

Step-by-step explanation:

Given :

Initial deposit = 40000

Amount of money = Initial deposit / Reserve rate

When reserve rate = 10% = 0.1

Amount of money = 40000 / 0.1 = 400,000

When reserve rate = 8% = 0.08

Amount of money = 40000 / 0.08 = 500,000

Difference = 500,000 - 400,000 = 100,000

Amount of money will increase by 100,000

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How heavy a load (pounds) is needed to pull apart pieces of wood 4 inches long and 1.5 inches square? Here are data from student
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Answer:

a. (29526.192 , 32155.808)

b. (29673.9301 , 32008.0699)

Step-by-step explanation:

on calculation, we find that sample mean = 30843 and sample standard deviation = 3018.504, and n=20

1)

Sample Mean = 30841

SD = 3000

Sample Size (n) = 20

Standard Error (SE) = SD/root(n) = 670.8204

alpha (a) = 1 - 0.95 = 0.05

z critical value for 95% confidence interval:

z(a/2) = z(0.025) = 1.96

Margin of Error (ME) = z(a/2) x SE = 1314.808

95% confidence interval is given by:

Sample Mean +/- (Margin of Error) = 30841 +/- 1314.808

= (29526.192 , 32155.808)

2)when std dev of population is not known, we use sample's, but we have to use t instead of z

Sample Mean = 30841

SD = 3018.504

Sample Size (n) = 20

Standard Error (SE) = SD/root(n) = 674.958

alpha (a) = 1-0.9 = 0.1

we use t-distribution as population standard deviation is unknown

t(a/2, n-1 ) = 1.7291

Margin of Error (ME) = t(a/2,n-1)x SE = 1167.0699

90% confidence interval is given by:

Sample Mean +/- (Margin of Error)

30841 +/- 1167.0699 = (29673.9301 , 32008.0699)

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