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2 years ago

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1 answer:

Gala2k [10]2 years ago

7 0

Number one. 897 2. Eight hundred eighty four and fourth seven hundredths. Number three. 17.818. 4. Two thousand forty four and four tenths. Number five. 22.766 6. Twelve thousand five hundred and twelve Number seven. 23.62

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Find the percent change:<br><br> $350 to $400

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Answer:

14.29% increase

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&x_1&y_1&x_2&y_2\\
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2 years ago

Pls help Factor 4x^3+32

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2 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

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Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

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2 years ago

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