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3 years ago

7

Is there someone that is on here that will help me with my geometry because I'm not getting any of this, please?

2 answers:

lara31 [8.8K]3 years ago

8 0

A nonagon had nine sides and the interiors angles equal 1260 degrees. X is on of those interior angles. So 1260/9 equals 140.
X =140

erma4kov [3.2K]3 years ago

3 0

The answer above is correct, however, if you are seeing more of these questions in the future and don't know how to do it. you take the amount of sides (9) - 2 to get 7. Then multiply by 180 to get 1260. 1260/9 is 140

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3 years ago

What is the measure of angle A?

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6 0

4 years ago

Read 2 more answers

HELP ASAP WILL MARK BRAINLIEST AREA OF FIGURES

Lerok [7]

Answer:

1. 170.083 in³

2. 126π in³

3. 92.106 m³

4. 2412.74 in³

5. 612π m³ and 1922 m³

Step-by-step explanation:

1.

Cylinder:

$V = \pi r^{2}h$ *Plug in numbers*

$(3.14)(2.5)^{2}(7)$ *Square 2.5*

$(3.14)(6.25)(7)$ *Solve*

≈ $137.375in^{3}$

Sphere:

$V = \frac{4}{3}\pi r^{3}$ *Plug in numbers*

$\frac{4}{3} (3.14)(2.5)^{3}$ *Cube 2.5*

$\frac{\frac{4}{3}(3.14)(15.625)}{2}$ *Divide by 2 and Solve*

≈ $32.7083 in^{3}$

Add both volumes

$137.375 + 32.7083$ ≈ $170.083in^{3}$

2.

Cylinder:

$V = \pi r^{2}h$ *Plug in numbers*

$\pi (3)^{2}(10)$ *Square 3*

$\pi (9)(10)$ *Multiply*

$90\pi$

Sphere:

$V = \frac{4}{3}$ π $r^{3}$ *Plug in numbers*

$\frac{4}{3}\pi (3)^{3}$ *Cube 3*

$\frac{4}{3} \pi (27)$ *Multiply*

$36\pi$

Add both Volumes to get total

$90\pi + 36\pi = 126in^{3}$

3.

Sphere:

$V = \frac{4}{3}\pi r^{3}$ *Plug in numbers*

$\frac{4}{3} (3.14)(3)^{3}$ *Cube 3*

$\frac{4}{3} (3.14)(27)$ *Multiply*

$113.04m^{3}$

Cone:

$V = \frac{\pi r^{2}h}{3}$ *Plug in numbers*

$\frac{(3.14)(2)^{2}(5)}{3}$ *Square 2*

$\frac{(3.14)(4)(5)}{3}$ *Solve*

$20.93m^{3}$

Subtract the volumes to get the volume of the blue area

$113.04 - 20.93 = 92.106m^{3}$

4.

Sphere:

$V = \frac{4}{3} \pi r^{3}$ *Plug in numbers*

$\frac{4}{3}\pi (8)^{3}$ *Cube 8*

$\\\frac{4}{3}\pi (512)$ *Multiply*

$\\\\\pi (682.6)$ *Solve*

$2133.66in^{3}$ *Divide by 2 since it's a hemisphere*

Cone:

$V = \frac{\pi r^{2}h}{3}$ *Plug in numbers*

$\frac{\pi (8)^{2}(20)}{3}$ *Square 8*

$\frac{\pi (64)(20)}{3}$ *Multiply and Divide*

$1340.41 in^{3}$

Add both volumes

$1072.33 + 1340.41 = 2412.74in^{3}$

5.

Cylinder:

$V = \pi r^{2}h$ *Plug in numbers*

$\pi (6)^{2}(16)$ *Square 6*

$\pi (36)(16)$ *Multiply*

$576\pi$

Cone:

$V = \frac{\pi r^{2}h}{3}$ *Plug in numbers*

$\frac{\pi (6)^{2}3}{3}$ *Square 6*

$36\pi$

Add both volumes

$576\pi + 36\pi = 612\pi m^{3}$

Alternative: *Multiply π*

$1922m^{3}$

4 0

3 years ago

Read 2 more answers