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iren [92.7K]
3 years ago
7

A rectangular yard is X feet wide. The yard is 4 feet longer than it is wide. The perimeter P of yard is given by the equation P

= 4x + 8. If the perimeter of the yard is 84 feet how long is the yard?
A. 19 feet
B. 23 feet
C. 24 feet
D. 28 feet
Mathematics
1 answer:
vladimir2022 [97]3 years ago
6 0

Given:

Width of the rectangular yard = x feet

Length of the rectangular yard = x+4 feet

Perimeter of the rectangular yard is:

P=4x+8

Perimeter of the yard = 84 feet

To find:

The length of the rectangular yard.

Solution:

Perimeter of the yard is 84 feet.

4x+8=84

4x=84-8

4x=76

Divide both sides by 4.

x=\dfrac{76}{4}

x=19

So, the width of the rectangular yard is 19 feet.

Length = 19+4

Length = 23

The length of the rectangular field is 23 feet.

Therefore, the correct option is B.

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The length of a rectangle 4 yd is longer than its width. If the perimeter of the rectangle is 68 yd, find its length and width.
natulia [17]

w + 4

------------------------

l l

l l w

l l

------------------------

Perimeter would be the sum of all the sides so: (w+4) + w + (w+4) + w

Perimeter is 60 yards according to your problem so: (w+4) + w + (w+4) + w = 60 yds

1.Simplify/combine like terms:

w + 4 + w + w + 4 + w =

4w + 8 =

Now it's a 2-step algebra equation

4w + 8 = 60

2.Subtract 8 on both sides

4w = 56

3.Divide both sides by 4

w = 14

4 0
3 years ago
27
katrin2010 [14]

Answer:

A  ≈ 35.3 units²

Step-by-step explanation:

Calculate the radius CB using Pythagoras' identity in the right triangle.

CB² + AB² = AC²

CB² + 6² = 9²

CB² + 36 = 81 ( subtract 36 from both sides )

CB²  = 45 = r²

Then area of quarter circle is

A = \frac{1}{4} × πr² = \frac{1}{4} × π × 45 ≈ 35.3

6 0
3 years ago
Please solve this for me i dont understand and i will be very appreciative
vredina [299]

Answer: b is for ░▒▓█ Ř █▓▒░

Step-by-step explanation:

5 0
3 years ago
What is the range of the function
fiasKO [112]

Answer:

d

Step-by-step explanation:

6 0
3 years ago
A car has mass 1500 kg and is traveling at a speed of 35 miles/hour. what is its kinetic energy in joules? (Be sure to convert m
photoshop1234 [79]

Answer:

Factor by which kinetic energy increase = 4 times

Step-by-step explanation:

Given,

  • Mass of the car, v1 = 1500 kg
  • initial speed of car = 35 miles/h

                               =\dfrac{35\times 1609.34}{3600}\ m/s

                               = 15.64 m/s

Initial kinetic energy of the car is given by,

k_1\ =\ \dfrac{1}{2}.m.v_1^2

       =\ \dfrac{1}{2}\times 1500\times (15.64)^2\ joule

       = 183606.46 J

  • Final velocity of car v2 = 70 miles/hour

                                      =\dfrac{70\times 1609.34}{3600}

                                      = 31.29 m/s

So, final kinetic energy of car is given by

k_2\ =\ \dfrac{1}{2}.m.v_2^2

        =\ \dfrac{1}{2}\times 1500\times (31.29)^2

        = 734425.84 J

Now, the ratio of final to initial kinetic energy can be given by,

\dfrac{k_2}{k_1}=\ \dfrac{734425.84}{183606.46}

=>\ k_2\ =\ 4k_1                      

Hence, the kinetic energy will increase by 4 times.

7 0
3 years ago
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