Solution:
4.2 x 10^6 bp/10^3 bp/seconds = 4.2 + 103 s which is 4200 seconds and equivalents to 70 minutes
In addition, assuming a pause of 2 seconds for re initiating after completing every okazaki fragment and assuming the okazaki fragments average 1000 nucleotide long.
4.2 x 10^6 bp/10^3 bp = 4200 okazaki fragments 4200 * 2 seconds = 8400 seconds which is 140 minutes or 2 hours 20 minutes of pauses alone.
Therefore, overall time would be pauses plus the 70 minutes so total time of 210 minutes. Assuming that the replisome completely disassociates from the DNA after every okazaki fragment and must spend one-minute rebinding.
4200 okazaki fragments. 60 seconds rebinding time per fragment: 4200 x 1 minute = 4200 minutes rebinding time plus 70 minutes for actual replication. 4200 minutes is 70 hours which is almost 3 days.
Answer:
Explanation:
A fall in temperature can also adversely affect cell and cell membranes. At low temperatures, the phospholipids' fatty acid tails are moving less and stiffer. This reduces the membrane's overall fluidity as well as reduces its permeability and perhaps limits the entry into the cells of vital chemicals like oxygen and glucose. Also, low temperatures can impede cell development by preventing cell size expansion.
In severe cases, such long term exposure to sub-freezing temperatures, fluid in the cell can start solidifying and can form crystals that breach the membrane and destroy the cell.
Just search it up on Socratic app
