Answer:
d.$5,000
Explanation:
In order to find the maximum amount of possible expansion in the money supply we will have to find the money multiplier. The formula for the money multiplier is
1/reserve ration =1/0.2=5
Now that we know that the multiplier is 5 we will multiply is by 1000 which is the initial deposit, to get the total possible expansion in the money supply, 1000*5= 5000
Answer:
Ttechnical assistants are junior-level administrative employees who report directly to the company manager or team leader. Their role is to provide both administrative and technical support for business clients or the internal team. Technical assistants work in a variety of fields including healthcare, computer science, manufacturing, and bankingg.
Explanation:
Answer:
Built-in gains tax is $13,020
.
Explanation:
The built-in gains tax is one levied against an S corporation that used to be a C corporation, or received assets from a C corporation.
Here,
Gain= $80,000
Loss= $10,000
Holds= $8,000
Income= $65,000
Corporate tax= 21%
To calculate the built-in gains tax, we will need to calculate the net gain of the corporation and multiply it by the tax rate.
= Built-in-gain - built-in-loss - unexpired NOL
80,000 - 10,000 - 8,000 = 62,000
Then
62,000 x 0.21 tax rate = 13,020
= 13,020
Answer:
Equivalent units of production= 229,300
Explanation:
Giving the following information:
Physical Units Work in process, May 1 (60%) 59100
Completed and transferred out 179500
Work in process, May 31 (40%) 49800
<u>To calculate the equivalent units, we need to use the following formula:</u>
Units completed in the period + Equivalent units in ending inventory WIP (units*%completion) = Equivalent units of production
Equivalent units of production= 179,500 + 49,800*1
Equivalent units of production= 229,300
Because the direct material is added at the beginning of the process, the %of completion is 100%.
Answer / Explanation:
Kindly note that the question is incomplete. However, kindly find the complete question below and the answer.
Complete Question
Water is flowing in a trapezoidal channel at a rate of Q=20m³/s . The critical depth y for such a channel must satisfy the equation:
0 = 1 − Q² / gA³c . B Where g= 9.81m /s² and Ac = the cross-section area can be related to depth y by B = 3+y and Ac = 3y+y²/2. Solve for the critical depth using (a). the graphical method,
Answer:
Given the equation,
0 = 1 − Q² / gA³c. B
Now substituting the given value g= 9.81m /s² , Q =20m³/s, B = 3+y, and Ac = 3y+y²/2,
We get:
0 = 1 - 20² / (9.81) ( 3y + y²/2)³ (3+y)
Hence we choose f(y) = 1 - 40.7747 / (3y + y²/2)³ . (3 + y) and solve for f(y) = 0
Therefore,
To solve using a graph, we take twelve sample points ( starting at y = 0.25 in step of 0.25m and plot a graph using MS- Excel. Kindly find the graph below.
2) As evident from the sample point and the graph function f(y) gets close to zero at y = 1.5, hence the root of f(y) = 0 is Xr = 1.5
