3 years ago

Evaluate Expressions

Mathematics

1 answer:

iren [92.7K]3 years ago

3 0

5(7)-7
35-7
28
The answer is: 28

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What is the average rate of change <br>y - 3 = -12 (x + 4)

vagabundo [1.1K]

Answer:

$- 12x$

Step-by-step explanation:

$y - 3 = - 12(x + 4) \\ y - 3 = - 12x - 48 \\ y = - 12x - 45$

Thr answer is the slope.

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2 years ago

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Please help!!!<br> Which expression is equivalent to (3m^-1n^2)^4/(2m^-2n)^3

Elza [17]

$\text{Use:}\\\\(a\cdot b)^n=a^nb^n\\\\(a^n)^m=a^{n\cdot m}\\\\\dfrac{a^n}{a^m}=a^{n-m}$

$\dfrac{(3m^{-1}n^2)^4}{(2m^{-2}n)^3}=\dfrac{3^4(m^{-1})^4(n^2)^4}{2^3(m^{-2})^3n^3}=\dfrac{81m^{-4}n^8}{8m^{-6}n^3}\\\\=10.125m^{-4-(-6)}n^{8-3}=10.125m^2n^5$

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2 years ago

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Express sin110 as ratio of acute angle

lesya [120]

Answer:

sin70°

Step-by-step explanation:

Given sin110° where 110° is an obtuse angle in the second quadrant.

The related acute angle in the first quadrant is 180° - 110° = 70°

Thus

sin110° = sin70°

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2 years ago

If a circle has a circumference of 38cm what is it’s radius to 0.1cm?

ira [324]

Answer:6.05cm

Step-by-step explanation:

Circumference=2×π×r

38=2×22/7×r

38×7=2×22×r

266=44r

r=266/44

r=6.05cm

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2 years ago

The weight, w, of a spring in pounds is given by 0.9 times the square root of the energy, E, stored by the spring in joules. If

frutty [35]

For this case we have the following equation:
$w = 0.9* \sqrt{E}$
Where,
w: The weight of a spring in pounds
E: the energy stored by the spring in joules.
Substituting values we have:
$w = 0.9* \sqrt{12}$
Making the corresponding calculation:
$w=3.12$
Answer:
the approximate weight of the spring in pounds is:
$w=3.12$

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2 years ago

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