You would need to use the pythagorean theorum which is would be 8 squared +x squared = 15 squared
Nothing to drag; nowhere to drag it to.
Park A's population can be modeled by
.. y = 150*1.2^x
Park B's population can be modeled by
.. y = 150*0.8^x
Answer:
z=3
Step-by-step explanation:
Add 3z and 2z
5z-5=25-5z
Add 5z on both sides to eliminate the -5z on the RHS
10z-5=25
Add 5 on both sides to eliminate the -5 on the LHS
10z=30
Divide by 10
z=3
Hope this helps!
Answer:
0 < x ≤ 12 and 0 < y ≤ 36
Step-by-step explanation:
Here, x represents the number of female gazelles and y represents the number of male gazelles.
The zoo only has room for 12 female gazelles.
∵ The number of rooms must be more than or equal to the total female gazelles ,
12 ≥ x
Also, number of animals can not be negative,
And, it must be greater than 0.
⇒ 0 < x ≤ 12,
⇒ 3(0) < 3x ≤ 3(12)
⇒ 0 < 3x ≤ 36
∵ Number of males gazelles = 3 × number of female gazelles
⇒ y = 3x
⇒ 0 < y ≤ 36
Hence, the constraints to represent a thriving population of gazelles at the zoo are,
0 < x ≤ 12,
0 < y ≤ 36
Answer:
8m(4+7p)
Step-by-step explanation:
