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Sati [7]
3 years ago
11

Irrational numbers are _____ integers.

Mathematics
1 answer:
Mariulka [41]3 years ago
6 0
Irrational number are alway, sometimes or never Integers. Hope this Helps!

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PLEASE HELP
slavikrds [6]

Answer:

B. Yes! Jason has printed 73/100 of the posters needed.

Step-by-step explanation:

7/10(1500) = 1050 minimum to print

1500-400 = 1100 printed

1100/1500 = 73/100

7 0
3 years ago
What are the next four multiples of the fraction 7/12
Vladimir79 [104]
7/12 14/24 21/36 28/48 35/60
7 0
3 years ago
Read 2 more answers
Three side lengths of a right triangle are given which side length should you substitute for the hypotenuse in Pythagorean theor
ankoles [38]

Answer:

The longest length which you are given.

Step-by-step explanation:

The hypotenuse is the longest side in a right angled triangle. The largest side in a right angled triangle is known as the hypotenuse.

8 0
3 years ago
Find the Domain and range of each relation. <br> 1. Q= {(3,4), (-4,1), (2,5), (-4,1), (0,0)}
zimovet [89]

Answer:

Step-by-step explanation:

domain is all ur x values.....

domain = { -4,0,2,3}....u only have to write them once if they repeat

range is all ur y values....

range = { 0,1,4,5}

7 0
3 years ago
Use two different methods to find an explain the formula for the area of a trapezoid that has parallel sides of length a and B a
evablogger [386]

Answer:

Formula of Trapezoid:

A = (a + b) × h / 2

The formula can be derived in different ways. for now, we have discussed two ways:

1. By using the formula of a triangle

2. By dividing into different sections

Step-by-step explanation:

1. By using the formula of a triangle

One of the ways to explain a formula for an area of a trapezoid using a formula for a triangle can be as follows.

Assume a trapezoid PQRS with lower base SR and upper base PQ (they are parallel) and sides PS and QR.

The image is attached below.

Connect vertices P and R with a diagonal.

Consider triangle ΔPQR as having a base PQ and an altitude from vertex R down to point M on base PQ (RM⊥PQ).

Its area is

S1=\frac{1}{2} *PQ*RM

Consider triangle ΔPRS as having a base SR and an altitude from vertex P up to point N on-base SR (PN⊥SR).

Its area is

S2=\frac{1}{2} *SR*PN

Altitudes RM and PN are equal and constitute the distance between two parallel bases PQ and SR.

They both are equal to the altitude of the trapezoid h.

Therefore, we can represent areas of our two triangles as

S1=\frac{1}{2}*PQ*h

S2=\frac{1}{2}*SR*h

Adding them together, we get the area of the whole trapezoid:

S=S1+S2=\frac{1}{2} (PQ+SR)h,

which is usually represented in words as "half-sum of the bases times the altitude".

2. By dividing into different sections

Trapezoid PQRS is shown below, with PQ parallel to RS.

Figure 1 - Trapezoid PQRS with PQ parallel to RS(image is attached below.)

We are going to derive the area of a trapezoid by dividing it into different sections.

If we drop another line from Q, then we will have two altitudes namely PT and QU.

Figure 2 - Trapezoid PQRS divided into two triangles and a rectangle. (image is attached below.)

From Figure 2, it is clear that Area of PQRS = Area of PST + Area of PQUT + Area of QRU. We have learned that the area of a triangle is the product of its base and altitude divided by 2, and the area of a rectangle is the product of its length and width. Hence, we can easily compute the area of PQRS. It is clear that

=> A_{PQRS} = (\frac{ah}{2}) + b_{1}h + \frac{ch}{2}

Simplifying, we have

=>A= \frac{ah+2b_{1+C} }{2}

Factoring we have,

=> A_{PQRS} = (a+ 2b_{1} + c)\frac{h}{2}  \\= > {(a+ b_{1} + c) + b_{1} }\frac{h}{2}

 But, a+ b_{1} + c  is equal to b_{2}, the longer base of our trapezoid.

Hence, A_{PQRS}= (b_{1} + b_{2} )\frac{h}{2}

We have discussed two ways by which we can derive area of a trapezoid.

Read to know more about Trapezoid

brainly.com/question/4758162?referrer=searchResults

#SPJ10

5 0
1 year ago
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