Answer:
24 minutes, 2:36 pm
Step-by-step explanation:
As working with hours is difficult because it does not use decimal system, lets work with minutes, not hours.
So, the clock is set to work normal at 3:00 pm and we need to get the minutes lost three days after. We know that, as 1 day has 24 hs, 3 days have 72 hours. Then, as our clock loses 2m after every 6 hs, we need to see how many 6hs are there in 72 hs. We do this bt dividing 72 by 6:
72/6 = 12
So, in 72 hours we will have 12 periods of 6hs. As our clock loses 2m after every 6 hs, in 3 days we will lose 2m 12 times. This is:
12 * 2 = 24
The clock loses 24 minutes.
Now we need to see the time it will read.
If there were no problems, the clock should read 3:00 pm after 3 days (72hs). But, as it lost 24 minutes, it will read 2:36 pm, it is, 24 minutes before 3:00 pm.
15 is the answer it is correct can
Sample answer: <span>For </span>f<span>(3), the input is 3 and you are looking for the output. To determine the function's value when </span>x<span> = 3, go to the value of 3 on the </span>x<span>-axis and then locate the graph for that value of </span>x<span>. Determine the value of </span>y<span> from the </span>y<span>-axis at that location on the graph.
Hope this helps
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(+3x+4y=2)
(+4x-4y=12)
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7x = 14
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7
X=2
3(2)+4y=2
6+4y=2
4y=-4
Y=-1.
Or you can plug x into the other equation.
4(2)-4y=12
8-4y=12
-4y=4
Y=-1.
The equation has no solution because:
5(n+10)=5n+10n
5n+10n=5n+10n
I subtract 5n from both sides
10n=10n
Only one side is supposed to have the variable which is n, so the equation has no solution.
