Answer:
The number of comic books did they have in all = 56
Step-by-step explanation:
The ratio of comics with Susan : Abe = 3 : 5
Let us assume the common factor on this ratio = m
So, the number of comics Susan has = 3 m
The number of comics Abe has = 5 m
Also, given: Abe had 14 more comic books than Susan
So, the number of comics Abe had = 14 + 3 m
⇒ 5 m = 3 m + 14
or, 2 m = 14, or m = 7
So, the number of books Susan has = 3 m = 3 x 7 = 21 books
The number of books Abe has = 5 m = 5 x 7 = 35
So, the book they have in all = 21 + 35 = 56
(4,1) is a possible solution. Hope this helps. :)
The correct expressions are
-8.8
11(-2)
-6.7
It would be 90m3 because all the angles are the same
Answer:
21 = 3 * 7
48 = 6 * 8 = (2 * 3) * (2 * 2 * 2) = 2^4 * 3
81 = 9 * 9 = (3 * 3) * (3 * 3) = 3^4
56 = 8 * 7 = (2 * 2 * 2) * 7 = 2^3 * 7
63 = 9 * 7 = (3 * 3) * 7 = 3^2 * 7
100 = 10 * 10 = (2 * 5) * (2 * 5) = 2^2 * 5^2
103 = 103
155 = 5 * 31
