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emmainna [20.7K]
3 years ago
6

Hi im giving away freee points.jst ay hi and you get 25 free po8nts.and.maby even brainliest ​

Mathematics
2 answers:
Crank3 years ago
6 0

Answer:

Hello

Step-by-step explanation:

Thanks for the free points

Hope you're having a good day

Y_Kistochka [10]3 years ago
4 0

Answer:

hey thx

Step-by-step explanation:

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You were assigned 225 pages to read. You finished ¼ of them. How many pages do you have left to read?
DENIUS [597]

Answer: 169 pages

Step-by-step explanation:

225-[1/4(225)]

225-56.25          ROUND DOWN

225-56

169 pages

7 0
3 years ago
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What is the recipricol of 1000​
Mrac [35]

The reciprocal of a number x is 1/x.

Let x = 1000

The reciprocal is 1/1000.

7 0
3 years ago
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Name two ways you can figure out an area of a composite figure.
TiliK225 [7]

Answer: they contain valuable items and are very interesting

Step-by-step explanation:

8 0
3 years ago
Weights of cars passing over a bridge part 2<br>​
DaniilM [7]

Step-by-step explanation:

The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.

Given:

mean,  mu = 3550 lbs (hope I read the first five correctly, and it's not a six)

standard deviation, sigma = 870 lbs

weights are normally distributed, and assume large samples.

Probability to be estimated between W1=2800 and W2=4500 lbs.

Solution:

We calculate Z-scores for each of the limits in order to estimate probabilities from tables.

For W1 (lower limit),

Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069

From tables, P(Z<Z1) = 0.194325

For W2 (upper limit):

Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954

From tables, P(Z<Z2) = 0.862573

Therefore probability that weight is between W1 and W2 is

P( W1 < W < W2 )

= P(Z1 < Z < Z2)

= P(Z<Z2) - P(Z<Z1)

= 0.862573 - 0.194325

= 0.668248

= 0.67 (to the hundredth)

6 0
3 years ago
What is the distributive property of 4 × 14
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