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3 years ago

19/3-3/4X=1/2X+5 Which number can each term of the equation be multiplied by to eliminate the fractions before solving?

Mathematics

1 answer:

Helen [10]3 years ago

7 0

Step-by-step explanation:

ते,,र,,रोयद्ल्य्फ्ल्य्द्त्फिफ्क्त्दोउ

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A line has a slope of 2 and passes through the point (3, 9). Which is the equation of the line?

Oxana [17]

We know, y - y1 = m(x - x1)
y - 9 = 2(x - 3)
y - 9 = 2x - 6
y = 2x + 3

In short, Your Answer would be Option B

Hope this helps!

3 0

3 years ago

Is AP Calculus more difficult than AP Statistics?

Natali5045456 [20]

Answer:

no both are "=" hard

Step-by-step explanation:

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3 years ago

Read 2 more answers

Calculate a_57 for the sequence {a_n}={-6,-9/2,-3,-3/2,0}

Archy [21]

Answer:the 57th term is 78

Step-by-step explanation:

The sequence is an arithmetic sequence. The formula for determining the nth term of an arithmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first term of the sequence.

d represents the common difference.

n represents the number of terms in the sequence.

From the information given,

a = - 6

d =3/2

n = 57

We want to determine the value if the 57th term, T57. Therefore,

T57 = - 6 + (57 - 1) ×3/2

T57 = - 6 + 56 × 3/2 = - 6 + 84

T57 = 78

3 0

3 years ago

The table lists how poverty level income cutoffs (in dollars) for a family of four have changed over time. Use the midpoint for

frez [133]

The poverty level cutoff in 1987 to the nearest dollar was $10787.

<h3>How to find a midpoint?</h3>

The midpoint as the point that divides the line segment exactly in half having two equal segments. Therefore, the midpoint presents the same distance between the endpoints for the line segment. The midpoint formula is: $\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)$ .

For solving this exercise, first you need plot the points in a chart. See the image.

Your question asks to approximate the poverty level cutoff in 1987 to the nearest dollar using the midpoint formula. Note that the year 1987 is between 1980 and 1990, thus you should apply the midpoint formula from data for this year (1987).

$\mathrm{Midpoint\:of\:}\left(1980,8429),\:\left(1990,13145):\quad \left(\frac{1990+1980}{2},\:\:\frac{13145+8429}{2}\right)\\\\ \\$

$\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\left(\frac{1990+1987}{2},\:\frac{13145+3843}{2}\right)\\ \\ =\left(\frac{3977}{2},\:\frac{21574}{2}\right)$

$\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\=(\frac{3977}{2},10787)$

The answer for your question will be the value that you calculated for the y-coordinate. Then, the poverty level cutoff in 1987 to the nearest dollar was $10787.

Read more about the midpoint segment here:

brainly.com/question/11408596

7 0

2 years ago

Please helllllllppppppppp

Harman [31]

(i) 2^6

(ii) 3^5

(iii) -1^14

(iv) 0.3^4

4 0

3 years ago