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bija089 [108]
3 years ago
15

How do I solve for x

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
7 0
Try multiplying all of your numbers together
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YOU DONT NEED TO DO ANYTHING JUST LET ME KNOW IF IM RIGHT OR NOT AND GIVE ME A REASON WHY IM CORRECT OR INCORRECT FOR 10 POINTS!
jeyben [28]

incoorect Step-by-step explanation:

Supplementary Angles  two angles that sum up to 180°

the other two sides are that and the other side is 70

7 0
3 years ago
How can you use number patterns to find the least common factor
Aleks04 [339]

Answer:

The correct answer is: 360.

Explanation:

First we can express 120 as follows:

2 * 2 * 2 * 3 * 5 = 120

You can get the above multiples as follows:

120/2 = 60

60/2 =30

30/2 = 15

15/3 = 5 (Since 15 cannot be divisible by 2, so we move to the next number)

5/5 = 1

Take all the terms in the denominator for 120, you would get: 2 * 2 * 2 * 3 * 5 --- (1)

Second we can express 360 as follows:

360/2 = 180

180/2 = 90

90/2 =45

45/3 = 15 (Since 45 cannot be divisible by 2, so we move to the next number)

15/3 = 5

5/5 = 1

Take all the terms in the denominator for 360, you would get: 2 * 2 * 2 * 3 * 3 * 5 --- (2)

Now in (1) and (2) consider the common terms once and multiple that with the remaining:

2*2*2*3*5 = Common between the two

3 = Remaining

Hence (2*2*2*3*5) * (3) = 360 = LCM (answer)

5 0
3 years ago
Quadrilateral ABCD is inscribed in circle 0 What is m<A
valentinak56 [21]
We know that
 A quadrilateral is inscribed in a circle if and only if the opposite angles are supplementary. ( Inscribed Quadrilateral Theorem)
so
m∠B+m∠D=180°
2x+(3x-5)=180
5x=180+5
5x=185
x=185/5
x=37°

m∠A=x+5-----> 37+5------> 42°

the answer is
m∠A is 42°

6 0
3 years ago
What would the correct answer be
Karo-lina-s [1.5K]
Think it would be true although I don’t know what the transistive property is. 

Hope this helps!
4 0
3 years ago
Read 2 more answers
Which expressions are polynomials?
igor_vitrenko [27]

Option A: z + 1

Option B: 6 + w

Option D: 2 x^{4}-y

Solution:

Let us first define the polynomial.

A polynomial can have constants, variables, exponents and fractional coefficients.

A polynomial cannot have negative exponents, fractional exponents and never divided by a variable.

<u>To find which expressions are polynomial:</u>

Option A: z + 1

By the definition, z + 1 is a polynomial.

It is polynomial.

Option B: 6 + w

By the definition, 6 + w is a polynomial.

It is polynomial.

Option C: y^{2}-\sqrt[3]{y}+4

y^{2}-\sqrt[3]{y}+4=y^{2}-{y}^{1/3}+4

Here, y have fractional exponent.

So, it is not a polynomial.

Option D: 2 x^{4}-y

By the definition, 2 x^{4}-y is a polynomial.

It is polynomial.

Hence z + 1, 6 +w and 2 x^{4}-y are polynomials.

6 0
3 years ago
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