ask some one who knows
you could ask a classmate
ask your mom dad or who ever you live with
<em>Hope this helps</em>
<span>Members lifted weights: W=32%
</span><span>Members preferred aerobics: A=41%
</span>Members preferred both: B=6%
Members lifted weights only: Wo=W-B=32%-6%→Wo=26%
Members preferred aerobics only: Ao=A-B=41%-6%→Ao=35%
F<span>ind the probability that the member prefers another method neither weights nor aerobics to exercise: N=?
N=100%-Wo-Ao-B
N=100%-26%-35%-6%
N=100%-67%
N=33%
Answer: T</span>he probability that the member prefers another method neither weights nor aerobics to exercise is 33%
95.44% IQ scores are between 77 and 125
We're given,
Mean (a)=101
standard deviation (b)=12
To find : ![P[77 < x < 125]](https://tex.z-dn.net/?f=P%5B77%20%3C%20x%20%3C%20125%5D)
Using Empirical Rule:
∴ 
![P[\frac{77-101}{12} < \frac{x-a}{b} < \frac{125-101}{12}]\\](https://tex.z-dn.net/?f=P%5B%5Cfrac%7B77-101%7D%7B12%7D%20%3C%20%5Cfrac%7Bx-a%7D%7Bb%7D%20%3C%20%5Cfrac%7B125-101%7D%7B12%7D%5D%5C%5C)
![=P[-2 < z < 2]\\](https://tex.z-dn.net/?f=%3DP%5B-2%20%3C%20z%20%3C%202%5D%5C%5C)
![=P[Z < 2]-P[Z < -2]\\](https://tex.z-dn.net/?f=%3DP%5BZ%20%3C%202%5D-P%5BZ%20%3C%20-2%5D%5C%5C)
=95.44% (approx)
Learn more about Empirical rule of IQ calculation here:
brainly.com/question/13077017
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