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2 years ago

Can someone help me with this math homework please!

Mathematics

1 answer:

labwork [276]2 years ago

7 0

Answer:

1/2

Step-by-step explanation:

When its talking about the result or output, look at the range, and then follow the line(s) back to the number(s) in the domain. Do the opposite when it's talking about the function of a certain number, e.g. f(4).

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Find the value of x.<br><br> Can someone help please?

Leya [2.2K]

A. is the correct answer

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2 years ago

What is equal to 3 * 3 * 3 * 3 * 3

ladessa [460]

Answer:

243 or 3^5

Step-by-step explanation:

You can do the product by multiplying starting from the left.

3 * 3 * 3 * 3 * 3 =

= 9 * 3 * 3 * 3

= 27 * 3 * 3

= 81 * 3

= 243

You can also change it to an exponential form.

3 * 3 * 3 * 3 * 3 = 3^5

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3 years ago

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Step-by-step explanation:bark brainliest plz

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3 years ago

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Round to the nearest tenth 4.1553

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Answer:

4.2

Step-by-step explanation:

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2 years ago

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the eccentricity of a hyperbola is defined as e=c/a. find an equation with vertices (1,-3) and (-3,-3) and e=5/2

Ksivusya [100]

Answer:

$\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1$ .

Step-by-step explanation:

If (α, β) are the coordinates of the center of the hyperbola, then its equation of the hyperbola is $\frac{(x - \alpha )^{2} }{a^{2} } - \frac{(y - \beta )^{2} }{b^{2} } = 1$ .

Now, the vertices of the hyperbola are given by (α ± a, β) ≡ (1,-3) and (-3,-3)

Hence, β = - 3 and α + a = 1 and α - a = -3

Now, solving those two equations of α and a we get,

2α = - 2, ⇒ α = -1 and

a = 1 - α = 2.

Now, eccentricity of the hyperbola is given by $b^{2} = a^{2}(e^{2} - 1) = 4[(\frac{5}{2} )^{2} -1] = 21$ {Since $e = \frac{5}{2}$ given}

Therefore, the equation of the given hyperbola will be

$\frac{(x + 1 )^{2} }{4} - \frac{(y + 3 )^{2} }{21} = 1$ . (Answer)

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2 years ago