3 years ago

Which term is any number that can be shown as the quotient of two integers?

Mathematics

1 answer:

inysia [295]3 years ago

8 0

Rational. Example 5/10

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How do you solve f(x) = x2 + x - 20?

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$\huge \bf༆ Answer ༄$

Let's solve ~

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: {x}^{2} + x - 20$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \: {x}^{2} + 5x - 4x - 20$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x(x + 5) - 4(x + 5)$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:(x + 5)(x - 4)$

It's factorized now ~ And if you want to find the zeros then equate the expression with 0.

And you will get ;

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:x = - 5 \: \: and \: \: 4$

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2 years ago

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3 years ago

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3 years ago

What is the factored form of x^3-1

polet [3.4K]

Answer:

the factors of x^3-1 are $x^3 -1 = (x-1) (x^2 +x+1)\\$

Step-by-step explanation:

We need to find factors of x^3 -1

$x^3-1 \\(x)^3 -(1)^3\\We \,\, know\,\, a^3 -b^3 = (a-b) (a^2 +ab + y^2) \\So, \,\, using\,\, the \,\, formula\,\,\\Here\,\, a= x \,\,and\,\, b= 1\\(x)^3 -(1)^3 = (x-1) (x^2 +x+1)\\$

So, the factors of x^3-1 are $x^3 -1 = (x-1) (x^2 +x+1)\\$

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....................

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