Answer:
A
Step-by-step explanation:
Check the attached file for the answer.
Answer:
7.
Solution given;
male=15
female=27
1st term=5*3
2nd term=3*3*3
now
Highest common factor=3
So
<u>The</u><u> </u><u>maximum</u><u> </u><u>number</u><u> </u><u>of</u><u> </u><u>groups</u><u> </u><u>that</u><u> </u><u>the</u><u> </u><u>teacher</u><u> </u><u>can</u><u> </u><u>make</u><u> </u><u>is</u><u> </u><u>3</u><u>.</u>
<u>and</u><u> </u><u>each</u><u> </u><u>team</u><u> </u><u>contains</u><u> </u><u>5</u><u> </u><u>male and</u><u> </u><u>9</u><u> </u><u>female</u><u>.</u>
One and eighty five. 1x85=85 but 85 isnt prime>>>
P(A) = 0.993 is the probability of event A
_
P(A) is the probability of not A (note that I am trying to place a bar over A. I hope you can see it, else it is because the editor did not show it as I intended)
Then, use the fact that the probability of A plus the probability not A is equal to 1:
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=> P(A) + P(A) = 1
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=> P(A) = 1 - P(A) = 1 - 0.993 = 0.007
So, the answers are:
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1) P(A) = 0.07
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2) Yes, A is unlikely because its probability is very low.
