Answer:
f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)
Step-by-step f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)explanation:
f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)f(x) f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)p(x + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(xf(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(xf(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1) + 1) – c, then (α + 1)(β + 1)f(x) = x2 – p(x + 1) – c, then (α + 1)(β + 1)
I don’t even know the answer to be honest
Answer:
6
Step-by-step explanation:
3+(-h)+(-4)
Let h = -7
3+(- -7)+(-4)
3+(7)+(-4)
10 -4
6
Perpendicular bisectors have a particular property: if AB is a perpendicular bisector of CD, then every point lying on AB has the same distance from C and D.
In your case, we have that every point lying on AC has the same distance from B and D.
So, in particular, we have EB=ED, because E lies on AC.
Moreover, since AC is a perpendicular bisector, it is the height of the triangle (if we choose BD as base), and it bisects BD: this means that the triangle is isosceles, so AD=AB.
This means that triangles ABE and ADE have:
- AD=AB because ABD is isosceles
- EB=ED because AC is the perpendicular bisector of BD
- AE in common
So, their sides are all equal, and thus they are congruent.
