I assume you mean x squared in the first equation
Because both are equal to y, they are equal to each other so x + 5 = x^2 +3
If we then move everything over to one side, we get x^2 - x - 2 = 0
Then factorise it to (x-2)(x+1) = 0
And solve both parts separately
x + 1 = 0
x = -1
x-2 = 0
x = 2
Sub both values into the simplest equation in this case y=x+5
to get y = 4 and y = 7
Answer: wwww
Step-by-step explanation:
Answer:
angle AEF is 60 degrees
Step-by-step explanation:
120 - 90 = 30
90 - 30 = 60
Answer:
Of all 6 faces it would be 150
Step-by-step explanation:
If one side of the cube is 5cm long, then l × w = area of a face, so if it is a cube then all 4 sides are the same on a face so 5 × 5 = 25, so 25 × 6 faces = 150
Problem 7)
The answer is choice B. Only graph 2 contains an Euler circuit.
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To have a Euler circuit, each vertex must have an even number of paths connecting to it. This does not happen with graph 1 since vertex A and vertex D have an odd number of vertices (3 each). The odd vertex count makes it impossible to travel back to the starting point, while making sure to only use each edge one time only.
With graph 2, each vertex has exactly two edges attached to it. So an Euler circuit is possible here.
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Problem 8)
The answer is choice B) 5
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Work Shown:
abc base 2 = (a*2^2 + b*2^1 + c*2^0) base 10
101 base 2 = (1*2^2 + 0*2^1 + 1*2^0) base 10
101 base 2 = (1*4 + 0*2 + 1*1) base 10
101 base 2 = (4 + 0 + 1) base 10
101 base 2 = 5 base 10
