We have to draw the model for 5 divide 1/7 . In order to draw the model we use below steps.
Draw 1/7 boxes to represent 1/7 groups.
Assume 5 as the number which represents the total of these 1/7 groups.
Put a question mark at the first box.
Attached is the model to represents 5 divide 1/ 7 .
5/(1/7)
5*7
35
In the question mark we should put 35.
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With base-ten blocks ,there would be the 3 units, 1 tens block , and five hundreds cubes
Answer:
Step-by-step explanation:
6cos^2(x) + 7cos(x) +2 = 0
Call cos(x) = y to change this to something a little bit more familiar.
6y^2 + 7y + 2 =0
This equation is a quadratic. Solve it first. Then we'll go back to solving for cos(x)
This equation factors into 2 possible answers
(3y + 2)(2y + 1) = 0
3y + 2 = 0
3y = - 2
y = - 2/3
2y + 1 = 0
2y = - 1
y = - 1/2
Now let's start with
cos(x) = - 1/2
That means that x is in quadrant two or three.
cos-1(1/2) = 60 degrees.
Quad 2: x = 180 - 60 = 120
Quad 3: x = 180 + 60 = 240
Now cos(x) = - 2/3
cos-1(2/3) = 48.19
Quad 2: x = 180 - 48.19 = 131.81
Quad 3: x = 180 + 48.19 = 228.19
Answer:
C. In step 2, Cindy should have multiplied both sides of the equation by 2.
Step-by-step explanation:
I'll go through the equation correctly, and then point out what would have happened.
3 = x/2 - 5
Add 5 to both sides. -5 and 5 cancel out.
8 = x/2
What Cindy should have done here is multiply by 2, not divide by 2. It is important to remember that you do the INVERSE operation to cancel out a number.
What would have happened here is that we have an extra step (though either way we still end up with x being 16.)
Correct Step 2:
Multiply both sides by 2. x/2 and 2x cancel out.
x = 16
Incorrect Step 2:
8/2 = (x/2)/2
4 = x/4
Multiply both sides by 4 (this would be the extra step!).
16 = x
