Write equivalent expressions for x-7.x-2 and x7\x2

Given f(x) = 5x2 2 and g(x) = 2x3 (f º g)(x) is a function of degree

IgorLugansk [536]

Suppose you are given the two functions f (x) = 2x + 3 and g(x) = –x2 + 5. Composition means that you can plug g(x) into f (x).

3 0

3 years ago

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WILL MARK BRAINLIEST. Which of the following statements about the polynomial function given is true?

Katyanochek1 [597]

Answer:

A.

Step-by-step explanation:

because as X approaches infinity, the negative sign will cause it to go opposite of X.

4 0

3 years ago

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Vertical plane R intersects horizontal plane P. Points A, D, and B are on the line of the intersecting planes. Point F is on the

Ugo [173]

Answer:

1. lineDB

2.H

3,D

Step-by-step explanation:

edge 2020

Brainliest would be appreciated

7 0

3 years ago

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Pls show full working out

sweet-ann [11.9K]

Answer:

Question 1a. i) $x=1.8m$

Question 1a. ii) $Volume=27.6m^3$

Question 1b) $Volume=65.9m^3$

Explanation:

Question 1 a. i) Find the value of x.

$tan(\theta )=\dfrac{opposite\text{ }leg}{adjacent\text{ }leg}$

For the smalll triangle you can write:

$tan(\theta )=\dfrac{x}{1m}$

For tthe big triangle:

$tan(\theta )=\dfrac{x+2.7m}{2.5m}$

Substitute:

$\dfrac{x}{1m}=\dfrac{x+2.7m}{2.5m}$

Solve for x:

$2.5x=x+2.7m\\\\2.5x-x=2.7m\\\\1.5x=2.7m\\\\x=2.7m/1.5\\\\x=1.8m$

Question 1a ii) Find the volume of the frustrum

Find the volume of a cone with height = 2.7m + 1.8m = 4.5m, and radius = 2.5m

Formula:

$Volume=(1/3)\pi \times radius^2\times height$

Substitute:

$Volume=(1/3)\pi \times (2.5m)^2\times 4.5m=9.375\pi m^3$

Find the volume of a cone with heigth = 1.8m and radius = 1m

$Volume=(1/3)\pi \times (1m)^2\times 1.8m=0.6\pi m^3$

Subtract the volume of the small cone from the volume of the big cone

$Volume\text{ }of\text{ }frustrum=9.375\pi m^3-0.6\pi m^3=8.775\pi m^3\approx 27.6m^3$

Question 1b. Calculate the volume of the bin

i) Upper frustrum

This is the same frustrum from the equation of above, thus ist volume is 27.6m³.

ii) Lower frustrum

$\dfrac{x}{2.0m}=\dfrac{x+2.4m}{2.5m}$

$2.5x=2(x+2.4m)\\\\2.5x=2x+4.8m\\\\0.5x=4.8m\\\\x=9.6m$

$Volume=(1/3)\pi \times (2.5m)^2\times (9.6m+2.4m)-(2.0m)^2\times (9.6m)$

$Volume=38.3m^3$

iii) Add the volume of the two frustrums

$Volume=27.6m^3+38.3m^3=65.9m^3$

6 0

3 years ago

-x over 6 -1=-13 show work pleaseee

xenn [34]

Answer:

x=-72

Step-by-step explanation:

-x/6-1=-13

add 1 to both sides

-x/6=-12

multiply 6*-12

-72

x=-72 because -72/6=-12

8 0

3 years ago