Let
L----------> <span>the length of the yard
W--------> </span><span>the width l of the yard
we know that
the perimeter is equal to
</span>
![P=2*[W+L]](https://tex.z-dn.net/?f=P%3D2%2A%5BW%2BL%5D)
![72=2*[W+L] \\ 36=W+L](https://tex.z-dn.net/?f=72%3D2%2A%5BW%2BL%5D%20%5C%5C%2036%3DW%2BL)
--------> equation 1
------> equation 2
<span>substitute equation 2 in equation 1
</span>
<span>
we know that
Area of the rectangular yard is equal to
</span>
<span>
</span>
Answer:
18 cookies
Step-by-step explanation:
3/4 = 75%
75% = 0.75
Multiply this by 24 = 18 cookies
Answer:
30.5 hours
Step-by-step explanation:
If he were to average 8 hours PER week for 4 weeks, his total sum would have been:
8 * 4 = 32 hours
But he fell short of it. By how much?
By 
hours!
So, he practiced 1 1/2 hours LESS THAN 32 hours, so his practice time is:
So, <u>he practiced 30.5 hours in the 4 weeks</u>
Let's say we use "x" of the 25% OJ... ok... well, how much juice is really in that "x" liters? well, 25% of it is OJ, the rest is water, how much is 25% of x? well, (25/100) * x, or 0.25x.
likewise, we'll use "y" of the 10% OJ, and it will end up with (10/100) *y or 0.10y of juice in it.
whatever "x" and "y" are, they must add up to 15 Liters, and the juice concentration on that mixture, must also be the sum of their sum concentration.
how much will be it of the 10% juice? well, y = 15 - x.
You can add 4/9.
A simple trick is to look at the numerator and denominator separately, if they're both perfect squares then you're good (4, 2^2, check. 9, 3^2, check.)
