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dezoksy [38]
3 years ago
15

PLEASE PLEASE HELP!!! Match each pair of matrices with its product matrix.

Mathematics
1 answer:
Butoxors [25]3 years ago
4 0

Answer:

Step-by-step explanation:

Did the calculations myself, probably too late for these to be of any use but I'll leaave them here anyways for anyone else that needs it in the future. Love yall!

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Find the amount of time. I=$237.90, P=$1525, r=2.6%<br><br> think I=PRT
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3 years ago
An object travels 4/5 mile in one half hour what is it’s speed in miles per hour
Anton [14]

4/5 mile in 1/2 hour.

1/2 * 2 = 1

4/5 * 2 = 8/5

8/5 miles per hour or 1.6 miles per hour

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The difference between twice a number and 16 is 30. Which math statement is an equation that represents this relationship?
AleksAgata [21]

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D

Step-by-step explanation:

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2 years ago
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Write down the explicit solution for each of the following: a) x’=t–sin(t); x(0)=1
Kay [80]

Answer:

a) x=(t^2)/2+cos(t), b) x=2+3e^(-2t), c) x=(1/2)sin(2t)

Step-by-step explanation:

Let's solve by separating variables:

x'=\frac{dx}{dt}

a)  x’=t–sin(t),  x(0)=1

dx=(t-sint)dt

Apply integral both sides:

\int {} \, dx=\int {(t-sint)} \, dt\\\\x=\frac{t^2}{2}+cost +k

where k is a constant due to integration. With x(0)=1, substitute:

1=0+cos0+k\\\\1=1+k\\k=0

Finally:

x=\frac{t^2}{2} +cos(t)

b) x’+2x=4; x(0)=5

dx=(4-2x)dt\\\\\frac{dx}{4-2x}=dt \\\\\int {\frac{dx}{4-2x}}= \int {dt}\\

Completing the integral:

-\frac{1}{2} \int{\frac{(-2)dx}{4-2x}}= \int {dt}

Solving the operator:

-\frac{1}{2}ln(4-2x)=t+k

Using algebra, it becomes explicit:

x=2+ke^{-2t}

With x(0)=5, substitute:

5=2+ke^{-2(0)}=2+k(1)\\\\k=3

Finally:

x=2+3e^{-2t}

c) x’’+4x=0; x(0)=0; x’(0)=1

Let x=e^{mt} be the solution for the equation, then:

x'=me^{mt}\\x''=m^{2}e^{mt}

Substituting these equations in <em>c)</em>

m^{2}e^{mt}+4(e^{mt})=0\\\\m^{2}+4=0\\\\m^{2}=-4\\\\m=2i

This becomes the solution <em>m=α±βi</em> where <em>α=0</em> and <em>β=2</em>

x=e^{\alpha t}[Asin\beta t+Bcos\beta t]\\\\x=e^{0}[Asin((2)t)+Bcos((2)t)]\\\\x=Asin((2)t)+Bcos((2)t)

Where <em>A</em> and <em>B</em> are constants. With x(0)=0; x’(0)=1:

x=Asin(2t)+Bcos(2t)\\\\x'=2Acos(2t)-2Bsin(2t)\\\\0=Asin(2(0))+Bcos(2(0))\\\\0=0+B(1)\\\\B=0\\\\1=2Acos(2(0))\\\\1=2A\\\\A=\frac{1}{2}

Finally:

x=\frac{1}{2} sin(2t)

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3 years ago
Which of these represents an integer?<br> a. -3 b. 4 c. 2 1/2 d. 6.2
Nitella [24]
B is the answer!!!!!!!!!!!!!!!!!!!!!!!!!
4 0
3 years ago
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