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castortr0y [4]
3 years ago
12

Which expression will solve for the area of the shaded portion, in square inches?

Mathematics
1 answer:
nika2105 [10]3 years ago
7 0

Answer:

I might be wrong but It's C

108-4

Step-by-step explanation:

I wrote on a sheet of paper and checked over my response to your question.

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A garden box has a perimeter of 18½ feet. If the length is 5 feet, what is the area of the garden box?
Travka [436]

Answer:

area=\frac{85}{4}feet^{2}

Step-by-step explanation:

1. Approach

Since it is given that the garden box is a rectangle, then the opposite sides are congruent. One can use this to their advantage, by setting up an equation that enables them to solve for the width of the rectangle. After doing so, one will multiply the width by the given length and solve for the area.

2. Solve for the width

It is given that the garden box is a rectangle. As per its definition, opposite sides in a rectangle are congruent. The problem gives the length and the perimeter of the rectangle, therefore, one can set up an equation and solve for the width.

perimeter=18\frac{1}{2}\\\\length=5

2(length+width)=perimeter

Substitute,

2(5+width)=18\frac{1}{2}

Conver the mixed number to an improper fraction. This can be done by multiplying the "number" part of the mixed number by the denominator of the fraction. Then add the result to the numerator.

2(5+width)=\frac{37}{2}

Inverse operations,

2(5+width)=\frac{37}{2}\\/2\\\\5+width=\frac{37}{4}\\-5\\\\width=\frac{17}{4}

3. Solve for the area

Now that one has solved for the width of the box, one must solve for the area. This can be done by multiplying the length by the width. Since the width is a fraction, one must remember, that when multiplying an integer by a fraction, one will multiply the integer by the numerator (the top of the fraction), and then simplify by reducing the fraction, if possible. Reducing the fraction is when one divides both the numerator and the denominator by the GCF (Greatest Common Factor).

length=5\\\\width = \frac{17}{4}

length*width=area

Substitute,

5*\frac{17}{4}\\\\=\frac{85}{4}

area=\frac{85}{4}feet^{2}

4 0
3 years ago
REALLY NEED HELP! PLEASE
Soloha48 [4]
D is the right answer because g is midpoint of ah and e is midpoint of ab and eg is parallel to bh so eg equals half bh
5 0
3 years ago
Read 2 more answers
Need help with this
harina [27]

Answer:

Qu. 8 = A (50) = 25w  as 125w x 125l = Area ; this because perimeter 500ft would always be a 3:5 ratio to the larger area. Therefore perimeter is 125+125 +125 +125 and = 500ft. However we can prove if 125 is any length or width then A(50)= 1/5 = 25   Qu 9)= I think last 2 are a function. Qu 10) Answer B is correct.

Step-by-step explanation:

5 0
3 years ago
55.405 greater than 55.045
Kobotan [32]
55.405 is bigger then 55.045
4 0
3 years ago
Read 2 more answers
Someonee helppp meee pleaseee
BARSIC [14]
8.3% is ur answer hope this helps 
3 0
3 years ago
Read 2 more answers
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