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romanna [79]
3 years ago
6

Please ASAP! Thanks y'all!

Mathematics
1 answer:
nordsb [41]3 years ago
5 0
(a) Since the segments AN and RI are parallel, the corresponding angles TAN and TRI are equal, and the corresponding angles TNA and TIR are equal. Angle ATN is obviously equal to angle RTI. With three matching angles, triangle TAN ~ triangle TRI 

<span>(b) Since AN is parallel to RI, the ratio AR/AT is equal to NI/TN. Thus, 2/8 = NI/12, NI = 3 cm</span>
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Jared‘s grandmother gave him $19 for his birthday he brought eight dollars worth of candy and spent another four dollars on a ne
cestrela7 [59]

Answer:

$7

Step-by-step explanation:

To solve this one we will subtract how much he spends from what he has.  At the start he had 19 and then spent 8 meaning he now has 8 less than when we started so 19-8 is 11.  He now as 11 dollars, then he spend another 4 meaning we have to subtract another 4 dollars.  11-4 is 7.  So he as 7 dollars left at the end.

I hope this helps and please don't hesitate to ask if there is anything still unclear!

7 0
3 years ago
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Write an equation in point-slope form for a line passes through the point (8,-7) and has a slope of 5/4.
fomenos

Answer:

y+7=5/4(x-8)

Step-by-step explanation:

y-y1=m(x-x1)

y-(-7)=5/4(x-8)

y+7=5/4(x-8)

8 0
3 years ago
Use the algebraic procedure explained in section 8.9 in your book to find the derivative of f(x)=1/x. Use h for the small number
Triss [41]

Answer:

By definition, the derivative of f(x) is

lim_{h\rightarrow 0}\frac{f(x+h)-f(x)}{h}

Let's use the definition for f(x)=\frac{1}{x}

lim_{h\rightarrow 0} \frac{\frac{1}{x+h}-\frac{1}{x}}{h}=\\lim_{h\rightarrow 0} \frac{\frac{x-(x+h)}{x(x+h)}}{h}=\\lim_{h\rightarrow 0} \frac{\frac{(-1)h}{x^2+xh}}{h}=\\lim_{h\rightarrow 0} \frac{(-1)h}{h(x^2+xh)}=\\lim_{h\rightarrow 0} \frac{-1}{x^2+xh)}=\frac{-1}{x^2+x*0}=\frac{-1}{x^2}

Then, f'(x)=\frac{-1}{x^2}

7 0
4 years ago
Write the equation of the line perpendicular to the line x - 3y = 9 and passing through the point (3,5).
PilotLPTM [1.2K]
Here is a sample problem
has to be perpendicular to y=(4/9)*x-2 and pass through 4,3,


y-b=m(x-a)
slope of -9/4 is perpendicular to slope of 4/9, as y=4/9x-2 has slope 4/9. Our point is (4,3) therefore.
y-3=-9/4*(x-4)
y-3=-9/4x+9
y=-9/4x+9+3
y=-9/4x+12
5 0
3 years ago
The two sets of data below show the number of bubbles blown in fifty trials using two different bubble solutions.
storchak [24]

Answer:

d

Step-by-step explanation:

i got it right

5 0
4 years ago
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