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3 years ago

HELP ASAP I WILL GIVE BRAINLIEST IF I CAN

Mathematics

1 answer:

WARRIOR [948]3 years ago

6 0

Answer: add 3

Step-by-step explanation:

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What number needs to be added to 4 and 7 so that the ratio of

il63 [147K]

Answer:

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The mean score on a set of 17 test is 72. Suppose two more students take the test and score 68 and 63. What is the new mean?

Masja [62]

Answer:

New mean=71.32

Step-by-step explanation:

The expression for the total initial score is;

T=M×S

where;

T=total initial score

M=mean score

S=number in the set

replacing;

T=unknown

M=72

S=17

replacing;

T=72×17=1,224

The total initial score=1,224

Determine the total score by;

total score=total initial score+total final score

where;

total initial score=1,224

total final score=(68+63)=131

replacing;

total score=1,224+131=1,355

Determine the new mean;

New mean=total score/new number

where;

total score=1,355

new number=(17+2)=19

replacing;

new mean=1,355/19=71.32

8 0

3 years ago

A card is drawn from a standard deck, not replaced, and another is drawn. What is the probability of choosing a heart then a spa

Llana [10]

Answer:

49/52

Step-by-step explanation:

5 0

2 years ago

Write a function rule for the following arithmetic sequence and use it to find the 224th term. Show your work.

zavuch27 [327]

Answer:

671 is the 224th term of the given series

Step-by-step explanation:

The given sequence is

2,5,8,11....

First term that is 2

common difference that is 3

we have to find 224th term

That is n =224

using $a_n=a+(n-1)d$

$a_{224}=2+(224-1)3$

On solving the above equation we get

$a_{224}=671$

Hence, 224th term of the given series is 671

5 0

2 years ago

Read 2 more answers

Sketch the equilibrium solutions for the following DE and use them to determine the behavior of the solutions.

GREYUIT [131]

Answer:

$y=\dfrac{1}{1-Ke^{-t}}$

Step-by-step explanation:

Given

The given equation is a differential equation

$\dfrac{dy}{dt}=y-y^2$

$\dfrac{dy}{dt}=-(y^2-y)$

By separating variable

⇒ $\dfrac{dy}{(y^2-y)}=-t$

$\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-dt$

Now by taking integration both side

$\int\left(\dfrac{1}{y-1}-\dfrac{1}{y}\right)dy=-\int dt$

⇒ $\ln (y-1)-\ln y=-t+C$

Where C is the constant

$\ln \dfrac{y-1}{y}=-t+C$

$\dfrac{y-1}{y}=e^{-t+c}$

$\dfrac{y-1}{y}=Ke^{-t}$

$y=\dfrac{1}{1-Ke^{-t}}$

from above equation we can say that

When t will increases in positive direction then $e^{-t}$ will decreases it means that ${1-Ke^{-t}}$ will increases, so y will decreases. Similarly in the case of negative t.

4 0

3 years ago