All categories

3 years ago

Uhm, yeah im not very good at math, i need to graduate man, someone help lol

Mathematics

1 answer:

mr_godi [17]3 years ago

5 0

Answer:

d=√73=8.544

Step-by-step explanation:

Find distance (d) between market (0,8) , court house(6,5) and library(6,-1)

d between two pint is :

d=√(x2-x1)²-(y2-y1)²

d between market and court house:

d=√(6-0)²+(5-8)²

d=√36+9=√45 = 6.7082 ≅6.71 rounded to the nearest hundredths

d between courthouse and the library:

d=√(6-6)²+(-1-5)²

d=√36=6

the distance that Runner A ran=6.71+6=12.71

the distance from the library to the school:

d=√(6-(-2))²+(-1-(-4))²

d=√8²+3²

d=√64+9

d=√73=8.544 ( rounded to the nearest hundredth)

Runner B went 8.544 further than Runner A before stopping at school ( which is the distance between the library and the school.

You might be interested in

in science class mrs.moore students were directed to weight a 300 gram mass on the balance scale tina weighed the object and rep

IrinaK [193]

Answer: 9 1/3%

Step-by-step explanation:

4 0

3 years ago

Find the area of △LKJ.

nirvana33 [79]

Answer:

$A=600\: u^{2}$

The correct answer is letter c.

Step-by-step explanation:

The area equation of a triangle is given by:

$A=\frac{bh}{2}$ (1)

Where:

b is the base

h is the height

Let's find first the angle MJK (α), using the tangent definition.

$tan(\alpha)=\frac{24}{32}$

$\alpha=tan^{-1}(\frac{24}{32})$

$\alpha=36.9^{\circ}$

Now, if α = 37° then β (angle JLK) must be:

$37^{\circ} + \beta + 90^{\circ}=180^{\circ}$

$\beta=53^{\circ}$

Now, we can find the distance ML using again the tangent definition:

$tan(\beta)=\frac{24}{ML}$

$ML=\frac{24}{tan(53)}$

$ML=18$

The base of the triangle LKJ will be:

$b=32+ML=32+18=50$

Therefore, using equation (1) the area of △LKJ will be:

$A=\frac{50*24}{2}$

$A=600\: u^{2}$

The correct answer is c.

I hope it helps you!

5 0

3 years ago

1. Complete these factor trees. 30 N--- 2 x O 2 xox

ch4aika [34]

2 × 15

3 × 5

2×3×5 = 30

Hope it helps

6 0

3 years ago

Band practice lasted 4/5 of an hour. 2/3 of that time was spent marching. How many minutes were they marching?

GuDViN [60]

Answer: They were marching for 32 minutes.

Step-by-step explanation: If you multiply the 4/5 times by 60 minutes (1 hour), then you will get 48 minutes. 48 minutes is the time of the band practice. Once you get that, then multiply that by 2/3 to get the amount of minutes marching. Once you multiply 2/3*48, you will get 32, which is how many minutes they were marching during band practice.

8 0

3 years ago

A dress costs $63. If the store is having a 20% off sale how much does the dress cost now

Eduardwww [97]

50.4$. All you have to do is multiply 63 by 0.20 ( which is another form on 20% h

63 x 0.20 would give us 12.6

Now you want to subtract that 12.6 from 63,

This will give you 50.4$ :)

6 0

3 years ago