All categories

2 years ago

What is the approximate area of the shaded sector in the circle below?

Mathematics

1 answer:

Nataly [62]2 years ago

8 0

Answer: I believe the answer is 51 inches squared

Step-by-step explanation:

You might be interested in

9( −5ℎ) in standard form

harkovskaia [24]

Answer:

Step-by-Step-explaination

9(−5ℎ) = - 45h

6 0

2 years ago

Read 2 more answers

The length of a picture frame is (8u - 12) inches. It’s width is 3/4 of its length. Express the width of the picture frame in te

dezoksy [38]

3/4(8u-12)..................

7 0

2 years ago

Which properties were used to solve the following problem?

Stels [109]

Step-by-step explanation:

25(2x) + 25(3y)

25 · (2 · x) + 25 · (3 · y)

(25 · 2) · x + (25 · 3) · y <em>Associative property </em><em>(a · b) · c = a · (b · c)</em>

(25 · 2)x + (25 · 3)y

(2 · 25)x + (3 · 25)y <em>Commutative property</em><em> a · b = b · a</em>

5 0

3 years ago

Plz help pretty easy

cricket20 [7]

a and d b and c that's the answer

4 0

3 years ago

Read 2 more answers

Find the solution set of the following quadratic equations using the quadratic formula.

oksian1 [2.3K]

Answer:

<h3> 1) $x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$ </h3><h3> 2) $x_1=-\dfrac13\,,\quad x_2=-3$ </h3>

Step-by-step explanation:

$x^2 - 7x + 9 = 0\quad\implies\quad a=1\,,\ b = -7\,,\ c=9\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-7)\pm\sqrt{(-7)^2-4\cdot1\cdot9}}{2\cdot1}=\dfrac{7\pm\sqrt{49-36}}2\\\\x_1=\dfrac{7+\sqrt{13}}2\,,\quad x_2=\dfrac{7-\sqrt{13}}2$

<h3>2)</h3><h3> $3x^2 + 10x=-3\\\\3x^2+10x+3=0\quad\implies\quad a=3\,,\ b =10\,,\ c=3\\\\x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot3}}{2\cdot3}= \dfrac{-10\pm\sqrt{100-36}}6\\\\x_1=\dfrac{-10+\sqrt{64}}6=\dfrac{-10+8}6=-\dfrac13\,,\qquad x_2=\dfrac{-10-8}6=-3$ </h3>

7 0

2 years ago