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3 years ago

The greatest integer that satisfies the inequality 1.6−(3−2y)<5

Mathematics

1 answer:

Cerrena [4.2K]3 years ago

6 0

Solve the inequality 1.6-(3-2y)<5.

1. Rewrite this inequality without brackets:

1.6-3+2y<5.

2. Separate terms with y and without y in different sides of inequality:

2y<5-1.6+3,

2y<6.4.

3. Divide this inequality by 2:

y<3.2

4. The greatest integer that satisfies this inequality is 3.

Answer: 3.

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Answer:

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Step-by-step explanation:

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Just divide 121 by 11 to get your answer.

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If tan theta = 10/13 and cos theta > 0 then sin2theta is what ?

svetoff [14.1K]

$sin2\alpha = \frac{260}{269}$

Step-by-step explanation:

We have , $Tan\alpha = \frac{Perpendicular}{Base} = \frac{10}{13}$ ,

We know that $sin\alpha = \frac{Perpendicular}{Hypotenuse} = \frac{Perpendicular}{\sqrt[2]{(Perpendicualr)^{2} + (Base)^{2})} }$

Substituting values of P & B , $sin\alpha = \frac{10}{\sqrt{10^{2} + 13^{2}} } = \frac{10}{\sqrt{269} }$

Now , $sin2\alpha = 2sin\alpha cos\alpha = 2sin\alpha \sqrt{1 - (sin\alpha)^{2} }$

⇒ $sin2\alpha =$ $\frac{10}{\sqrt{269} }$ × $\sqrt{1 - (\frac{10}{\sqrt{269} })^{2} }$ ×2

⇒ $sin2\alpha = \frac{20}{\sqrt{269} }( \sqrt{\frac{269 - 100}{269} } )$

⇒ $sin2\alpha = \frac{20}{\sqrt{269} }( \sqrt{\frac{169 }{269} } )$

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⇒ $sin2\alpha = \frac{260}{269}$

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3 years ago

Suppose that when your friend was born, your friends parents deposited $2000 in an account paying 5.9% interest. What will the a

irina1246 [14]

Answer:

FV= $4,725.74

Step-by-step explanation:

Giving the following information:

Initial investment (PV)= $2,000

Number of periods (n)= 15 years

Interest rate (i)= 5.9% = 0.059

To calculate the Future Value, we need to use the following formula:

FV= PV*(1 + i)^n

FV= 2,000*(1.059^15)

FV= $4,725.74

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3 years ago

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yan [13]

Answer:

Step-by-step explanation:

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2 years ago