For the units positions of all numbers we have:

From this we can conclude that total sum of these three numbers is 14. Number 1 we carry to next step. So we have:

For the tens positions of all numbers we have:

The extra number 1 on left side comes from the carry from last step. Similar to ones position we know that total sum is 11.

Now we insert x and z to find out y:

Now we need to find out the product of these three numbers:
Answer:
$1582
Step-by-step explanation:
cost of each kg 904/8=113
cost of 14 kg 113x14=1582
the cost of 14 kg of butter is $1582
For part A: you will get 3 linear factors (as the degree of the polynomial is 3). perform the division using (x-1) as your known factor and you will get (x-1)(2x²+11x+15). you can then factor the (2x²+11x+15) to get 2x^3 + 9x^2 + 4x - 15 = (x-1)(2x+5)(x+3)
for part B: since 2x+5 will provide the greatest value (assuming x>0) of the 3 factors, then 2x+5=13. solve to get x=4. if x is 4, then the dimensions are 3'x13'x7' [just sub 4 into the x's for each factor]
for part C: as to the graphing calculator, I don't have one. However, if you solve each linear factor for when it is 0, those values will be the x-intercepts. So your graph should cross the x-asix at 1, -5/2, and -3