The greatest integer that satisfies the inequality 1.6−(3−2y)<5

Mathematics

1 answer:

Cerrena [4.2K]3 years ago

6 0

Solve the inequality 1.6-(3-2y)<5.

1. Rewrite this inequality without brackets:

1.6-3+2y<5.

2. Separate terms with y and without y in different sides of inequality:

2y<5-1.6+3,

2y<6.4.

3. Divide this inequality by 2:

y<3.2

4. The greatest integer that satisfies this inequality is 3.

Answer: 3.

You might be interested in

A number is equal to three times the smaller number also the sum of the smaller number and four is the larger number situation i

emmainna [20.7K]

Answer:

this question is missing needed information

8 0

2 years ago

Jason decided that he will sell his stocks if their value per share (x) goes below $5 or above $15. Which compound inequality re

Veronika [31]

Answer:

B. x < $5 or x > $15

Step-by-step explanation:

The "or" in the problem statement gives you a clue that answer choices C and D can be rejected.

If x is the stock value, then value per share "below $5" means x < $5. This corresponds with answer choice B. Of course, "above $15" means x > $15, also corresponding to answer choice B.

3 0

2 years ago

Solve for x, 0 ≤ x ≤2π (2cosx-1)(2sinx+√3 ) = 0

vladimir1956 [14]

Answer:

x = π/3, x = 5π/3, x = 4π/3

Step-by-step explanation:

Let's split the given equation (2cosx-1)(2sinx+√3 ) = 0 into two parts, and solve each separately. These parts would be 2cos(x) - 1 = 0, and 2sin(x) + √3 = 0.

$2\cos \left(x\right)-1=0,\\2\cos \left(x\right)=1,\\\cos \left(x\right)=\frac{1}{2}$

Remember that the general solutions for cos(x) = 1/2 are x = π/3 + 2πn and x = 5π/3 + 2πn. In this case we are given the interval 0 ≤ x ≤2π, and therefore x = π/3, and x = 5π/3.

Similarly:

$\:2\sin \left(x\right)+\sqrt{3}=0,\\2\sin \left(x\right)=-\sqrt{3},\\\sin \left(x\right)=-\frac{\sqrt{3}}{2}$