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cupoosta [38]
3 years ago
13

Find the sum of the interior angle measures of a regular polygon with 17 sides

Mathematics
1 answer:
vova2212 [387]3 years ago
4 0

Answer:

2700

Step-by-step explanation:

the formula is (n - 2) 180

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Can anyone help me with my homework please
Over [174]
1..... 8(x+6)=-64
8x+48 =-64
8x =-64-48

8x=-112
X=-112/8
x=-14....

2.....3(4-2y)=-15
12-6y=-15

-6y=-15-12

-6y = - 27
y=27/6

y=4½....

3.....8w-3w+6=41
5w=41-6
5w=35
W=35/5
w=7....

4.....9x+3+x=-77

10x=-77-3
10x=-80
x=-8...

5.....10(-x-2)=120

-10x-20=120

-10x=120+20
-10x=140
x=140/-10
x=-14...

You shouldn't have a problem with the rest now....
7 0
3 years ago
Read 2 more answers
For the data set 16, 17, 18, 19, 30, the mean is 20. What is the
torisob [31]

Answer:

4

Step-by-step explanation:

i. d k I just entered the data into calculator

6 0
3 years ago
Read 2 more answers
[Question Deleted 5/15/2021]
pav-90 [236]

[Question Deleted 6/15/2021]

lets play this

anyone can do it ima go to sleep lol

7 0
3 years ago
Which graph shows y=3⌈x⌉+1?
vovangra [49]

Answer:

Its the bottom-right one

Step-by-step explanation:

Have a good day

8 0
2 years ago
Find the area of the triangle ABC with the coordinates of A(10, 15) B(15, 15) C(30, 9).
lions [1.4K]

Check the picture below.  so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}

(\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill

\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}

6 0
2 years ago
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