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valentina_108 [34]
2 years ago
5

Please just help me simplify these NOT SOLVE THEM IF AT ALL POSSIBLE! THANKS!!!​

Mathematics
1 answer:
alexandr402 [8]2 years ago
3 0

5th question: \frac{-8-4a}{-4} =2 + a

6th question: 11(-4q +3d + 3) = -44q +33d+33

7th question: \frac{15w +5-35w}{-5} =-3w-1+7w=4w-1

8th question: 4(y-1)+9(y+2) = 4y-4 + 9y+18= 13y+14

Hope it helps!

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What is the total surface area of the rectangular prism?​
bogdanovich [222]

Answer:

Total surface = 102.4 cm^2 (second answer in the list of options)

Step-by-step explanation:

Notice that we need to add the surface of 4 rectangles, two have smaller sizes than the other two. A pair of rectangles are 7.2 cm x 4 cm = 28.8 cm^2, while the other pair has 7.2 cm x 2 cm = 14.4 cm^2

There are also two equal bases each one of size 4 cm x 2 cm = 8 cm^2

Now we add two of each of the individual surfaces discussed above to complete the total surface area:

2 * 28.8 + 2 * 14.4 + 2 * 8 =  102.4 cm^2

which agrees with the second answer option provided.

3 0
3 years ago
The center of a circle is (4, 6), and an endpoint of a diameter is (2, 5). What is the other endpoint of the diameter?
valentinak56 [21]
Consider this option:
1. if the point (4;6) is the centre of the circle and the point (2;5) is the first endpoint of its diameter, then point (4;6) is the middle point of the diameter (it means that is the middle between the 1st and the 2d endpoints of diameter).
2. using the property described above:
for x of the 2d endpoint of the diameter: x=4*2-2=6;
for y of the 2d endpoint of the diameter: y=6*2-5=7.

answer: (6;7)
3 0
3 years ago
Read 2 more answers
In a naval engagement, one-third of the fleet was captured, one-sixth was sunk, and two ships were destroyed by fire. One-sevent
Otrada [13]

Answer:

60 ships.

Step-by-step explanation:

Let the total number of ships in the naval fleet be represented by x

One-third of the fleet was captured = 1/3x

One-sixth was sunk = 1/6x

Two ships were destroyed by fire = 2

Let surviving ships be represented by y

One-seventh of the surviving ships were lost in a storm after the battle = 1/7y

Finally, the twenty-four remaining ships sailed home

The 24 remaining ships that sailed home =

y - 1/7y = 6/7y of the surviving fleet sailed home.

Hence

24 = 6/7y

24 = 6y/7

24 × 7/ 6

y = 168/6

y = 28

Therefore, total number of ships that survived is 28.

Surviving ships lost in the storm = 1/7y = 1/7 × 28 = 4

Total number of ships in the fleet(x) =

x = 1/3x + 1/6x + 2 + 28

Collect like terms

x - (1/3x + 1/6x) = 30

x - (1/2x) = 30

1/2x = 30

x = 30 ÷ 1/2

x = 30 × 2

x = 60

Therefore, ships that were in the fleet before the engagement were 60 ships.

3 0
3 years ago
Subtract.
Yakvenalex [24]
1345 - (-853) = D) 2198.

Simplify your brackets to get: 1345 + 853 and then add which will get you your answer, 2198.

8 0
3 years ago
Read 2 more answers
Select True or False for each equation
7nadin3 [17]
True, false, false, true
7 0
3 years ago
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