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2 years ago

11

Roger served 5/8 pound of crackers, which was 2/3 of the entire box. what was the weight of the crackers originally in the box

1 answer:

ira [324]2 years ago

4 0

5/8 = 2/3 the entire box

Half of 2/3 is 1/3, and 2/3 + 1/3 = 1

So find half of 5/8 and add it to 5/8.

5/8 * 1/2 = 5/16

5/8 + 5/16

Change 5/8 to a fraction with a denominator of 16:

10/16 + 5/16 = 15/16

So the original weight is 15/16 pounds.

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The possible values of x are given by x+8=<6.<br><br>The greatest possible value of 7x is_____

kozerog [31]

Answer:

The possible values of x is given by $x\leq -2$ and they include: -2, -3, -4, -5, -6 and so on

The greatest possible value of 7x is $-14$

Step-by-step explanation:

We are given the equation: x + 8 <= 6

Let collect the like terms:

$x + 8 \leq 6\\x\leq 6 -8\\x \leq -2$

Therefore, x <= -2 and the possible values include: -2, -3, -4, -5, -6 and so on

To find the greatest possible value of 7x is when x = -2.

$7x = 7 * -2\\7x = -14\\$ .

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2 years ago

Given \qquad m \angle LONm∠LONm, angle, L, O, N is a straight angle. \qquad m \angle MON = 8x - 13^\circm∠MON=8x−13 ∘ m, angle,

Tamiku [17]

Answer:

<h3> $\boxed{99°}$ </h3><h3 />

Step-by-step explanation:

m<MON = 8x - 13°

m<LOM = 7x - 17°

To find : m <MON

First, we have to find the value of x :

Create an equation

$\mathrm{8x - 13 + 7x - 17 = 180}$ ( sum of angle in straight line )

Collect like terms

$\mathrm{15x - 13 - 17 = 180}$

Calculate

$\mathrm{15x - 30 = 180}$

Move constant to R.H.S and change its sign

$\mathrm{15x = 180 + 30}$

Calculate the sum

$\mathrm{15x = 210}$

Divide both sides of the equation by 15

$\mathrm{ \frac{15x}{15} = \frac{210}{15} }$

Calculate

$\mathrm{x = 14}$

Now, let's find the value of m<MON

$\mathrm{8x - 13}$

Plug the value of x

$\mathrm{ = 8 \times 14 - 13}$

Calculate the product

$\mathrm{ = 112 - 13}$

Calculate the difference

$\mathrm{ = 99}$ °

Hope I helped!

Best regards!

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