First, you have to find the median, which is the number in the middle: 25
Then cut the data in half by the median, so your new data sets are
15,29,20
and
31,38,41
Now you find the median of both of those sets, which is 29 and 38.
The interquartile range is the difference between the numbers, so 38-29 = 9.
Easy the answer to this question is 30
Answer:
0.61 or 8.79
Step-by-step explanation:
h = 47t − 5t²
27 = 47t − 5t²
5t² − 47t + 27 = 0
Quadratic formula:
t = [ -b ± √(b² − 4ac) ] / 2a
t = [ -(-47) ± √((-47)² − 4(5)(27)) ] / 2(5)
t = (47 ± √1669) / 10
t ≈ 0.61 or 8.79
5, since 10 to the fifth power is 100,000